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3 years ago

The sum of all but one interior angle of a heptagon is 776°. The final angle must have a measure of

Mathematics

2 answers:

Irina18 [472]3 years ago

7 0

Answer:

The final angle must have a measure of 124 degrees.

Step-by-step explanation:

Heptagon is polygon with seven sides.

Sum of angles of heptagon = 900°

Given:Sum of all angles and one interior angle of a heptagon is 776°.

Let the measure of interior angle be x

776° + ∠x = 900°

∠x = 900° - 776° = 124°

The final angle must have a measure of 124 degrees.

shutvik [7]3 years ago

5 0

A heptagon has 7 sides.

Sum of all interior angles = (7 - 2) x 180 = 900°

900 - 776 = 124°

Answer: The final angle must be 124°

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scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

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d -----> distance in feet

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$f(d)=1.11\sqrt{d}$

Part a): Determine f(2) and explain what it represents

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f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

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substitute in the function above and solve for f(2)

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What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

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Answer:

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Can someone please help me with this question?!? I am so confused and I don't know how to answer it.

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Answer:

a. f(0) = 1

b. DNE (does not exist)

c. DNE

d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

f(0) = 1

f(2) does not exist. There is a "hole" in the function definition there.

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

In summary, ...

a) f(0) = 1

b) lim x → 0 does not exist

c) f(2) does not exist

d) lim x → 2 = 3

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<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

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