What type of logic does using a calculator use?

1 answer:

6 0

Is a portable electronic devise used to perform operations ranging from arithmetic to complex mathematics. It was developed in the parallel with the analog computers of the day.
HOPE THIS HELPED A LOT D:

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Help me plz i need it

ycow [4]

4.Answer is $2.55
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7 0

3 years ago

Can someone review this and tell me if i'm right?

telo118 [61]

Yes you are right from what i seen

3 0

4 years ago

Which values from the set (-6,-4,-2,0,2,4,6) Satisfy this inequality? 3+1/2x>4

VMariaS [17]

Answer:-6 and -4

Step-by-step explanation:

5 0

3 years ago

A man rides a bicycle a distance of 48 miles in a certain amount of time. If the man increased his speed by 2 miles per hour, he

seropon [69]

Recall your d = rt, distance = rate * time.

so, in his usual speed, say is hmm "r" mph, so in his usual "r" speed, he rolls on for the 48 miles and it takes him "t" hours to get there.

now, if he increases his speed by 2 mph, then his new speed is "r + 2", and he arrives there 4 hours earlier, so if he took "t" hours going at "r" speed, then when he's going faster at "r + 2", he only takes "t - 4" hours, for the same 48 miles.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{usual speed}&48&r&t\\
\textit{faster speed}&48&r+2&t-4
\end{array}
\\\\\\
\begin{cases}
48=rt\implies \frac{48}{r}=\boxed{t}\\
48=(r+2)(t-4)\\
----------\\
48=(r+2)\left( \boxed{\frac{48}{r}}-4 \right)
\end{cases}
\\\\\\
48=(r+2)\left( \cfrac{48-4r}{r} \right)\implies 48r=(r+2)(48-4r)
$

$\bf 48r=48r-4r^2+96-8r\implies 0=-4r^2+96-8r
\\\\\\
4r^2+8r-96=0\implies r^2+2r-24=0
\\\\\\
(r+6)(r-4)=0\implies r=
\begin{cases}
-6\\
\boxed{4}
\end{cases}$

it cannot be a negative value, since is just a forward speed rate, so can't be -6.

8 0

3 years ago

Read 2 more answers

The sum of 2 consecutive integers is one less than 3 times the smaller integer find the 2 integers

aalyn [17]

The two consecutive integers are 2 and 3

Solution:

Let x and x + 1 are the two consecutive integers

Let "x" be the smallest integer

Let "x + 1" be the larger integer

Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer

Therefore,

sum of 2 consecutive integers = one less than 3 times the smaller integer

sum of 2 consecutive integers = 3 times the smaller integer - 1

x + x + 1 = 3(x) - 1

2x + 1 = 3x - 1

3x - 2x = 1 + 1

x = 2

Thus the smaller integer = x = 2

Larger integer = x + 1 = 2 + 1 = 3

Thus the two consecutive integers are 2 and 3

5 0

4 years ago