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sergejj [24]
3 years ago
14

Sasha has a rectangular garden 8 m by 10 m. The garden has a path surrounding it which is 2 m wide. What is the total area of th

e garden and pathway? A. 168 m^2 B. 120 m^2 C. 116 m^2 D. 96 m^2 E. 84 m^2
Mathematics
1 answer:
hoa [83]3 years ago
3 0

Answer:

b

Step-by-step explanation:

Area of a rectangle = length x width

length = 8 + 2 = 10

width = 10 + 2 = 12

10 x 12 = 120

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Can someone please help with this question pleaseee
Ulleksa [173]

Answer: Choice C) 10.5

The distance from A to C is 7 units (count out the spaces between the two points, or subtract y coordinates 4-(-3) = 4+3 = 7)

Let AC = 7 be the base of the triangle. You might want to rotate the image so that AC is laying horizontally rather than being vertical.

Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.

base = 7, height = 3

area of triangle = (1/2)*base*height

area of triangle = 0.5*7*3

area of triangle = 10.5 square units

7 0
3 years ago
Read 2 more answers
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Line AC is perpendicular to the
IRINA_888 [86]

If the length of OA is 1.80 units. Then the length of segment AB will be 0.80 units.

<h3>What is a Pythagoras theorem?</h3>

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

Line AC is perpendicular to the circle centered at O with a radius of 1 unit. The length of AC is 1.5 units.

The figure is shown below.

Then the length of segment AB will be

AB = OA - OB

AB = OA - 1

Then the OA will be

OA² = OC² + AC²

OA² = 1² + 1.5²

OA² = 1 + 2.25

OA² = 3.25

OA = 1.80 units

Then we have

AB = 1.80 - 1

AB = 0.80 units

More about the Pythagoras theorem link is given below.

brainly.com/question/343682

#SPJ1

7 0
2 years ago
HRW CAN U TRY AND HELP OLZZZZZ !!!!
Molodets [167]

Answer :  I thinks it’s 3

6 0
3 years ago
Sketch the region bounded by the curves y=3x3, x+y=4, and y=0. Find the coordinates of the centroid.
Scilla [17]
The graph of the region is attached.  The coordinates of the centroid are (5/3, 1).

The coordinates of the centroid are found by averaging the coordinates of the region;

Oₓ = (Aₓ+Bₓ+Cₓ)/3 = (0+1+4)/3 = 5/3
O(y) = (A(y) + B(y) + C(y)) = (0+3+0)/3=3/3=1

5 0
3 years ago
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