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3 years ago

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Which of the following demonstrates the Distributive Property? (4 points) 3(4a + 2) = 12a + 6 3(4a + 2) = 12a + 2 3(4a + 2) = 4a

+ 6 3(4a + 2) = 7a + 5

1 answer:

Anastasy [175]3 years ago

6 0

1. 12a+6=12a+6
2. 12a+6=12a+2
3. 12a+6=4a+6
4. 12a+6=7a+5

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K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

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2 years ago

What does 3 exponent -2 equal

inysia [295]

I am pretty sure your answer is going to be 243
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3 years ago

If 2a+4b=5 and a is equal to three times b, what is 3a?

IrinaK [193]

Answer:

3a=4.5

Step-by-step explanation:

it says that "a is equal to 3 times b", which translates to a=3b

We can substitute a as 3b in 2a+4b=5

2(3b)+4b=5

multiply

6b+4b=5

add

10b=5

divide by 10

b=1/2

since it's given that a=3b, we can multiply 1/2 by 3

a=3/2

3a is 3 times a, so we can mutiply 3(3/2)=9/2=4.5

Hope this helps!

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2 years ago

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2 years ago

Read 2 more answers

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

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3 years ago