For the first picture it’s the last one, for the second picture it’s y=x-2
12 days
8 / (2/3)
or
it takes 3 days to read 2 chapters so
3 X 4 = 12
For the first question the problem is simple. He is essentially going around 2 sides of a triangle, instead of along the hypotenuse. You would have to use Pythagoras' theorem for the real answer, a^2 + b^2 = c^2. However, for question 15, i don't know, I'm pretty sure this is an American question and I'm British, I don't believe I have ever encountered ordered pairs, or at least i don't remember learning them. Hope this helps ;)
Answer:
C) m∠1 = 45°, m∠2 = 76°, m∠3 = 80°
Step-by-step explanation:
In the given figure. There are two triangles. We have to use the concept of the sum of interior angles of a triangle is 180°.
So,
m∠2 + 45° + 59° = 180
m∠2 + 104° = 180°
m∠2 = 180° -104°
m∠2 = 76°
m∠1 and 45° are the opposite angles. When two lines are intersection each there, then the opposite angles must be equal.
Therefore, m∠1 = 45°
m∠1 + m∠3 + 55° = 180
45° + m∠3 + 55° = 180°
m∠3 + 100° = 180°
m∠3 = 180° -100°
m∠3 = 80°
Therefore, m∠1 = 45°, m∠2 = 76°, m∠3 = 80°
Answer is C) m∠1 = 45°, m∠2 = 76°, m∠3 = 80°
