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3 years ago

How many 2/5 are in 4?

1 answer:

6 0

For this case what we must do is a division using the following relationship:
 $N = (total amount) / (partial amount)
$ Substituting values we have:
 $N = (4) / (2/5)
$
 Rewriting the fraction we have:
 $N = (20) / (2)
$
 Simplifying we have:
 $N = 10
$
 Answer:
The number of times repeated 2/5 for 4 is:
10

You might be interested in

How do I confirm that f and g are inverses?

Anestetic [448]

Answer:

see explanation

Step-by-step explanation:

To show f and g are inverses we require to show that

f(g(x)) = x and g(f(x)) = x

f(g(x))

= f(6x - 4)

= $\frac{6x-4+4}{6}$ = $\frac{6x}{6}$ = x

-----------------------------------------------------------------------------

g(f(x))

= g( $\frac{x+4}{6}$ )

= ( 6 × $\frac{x+4}{6}$ ) - 4

= x + 4 - 4 = x

-------------------------------------------------

Hence f and g are inverses

4 0

3 years ago

Center c of the circle above has coordinates of (4, 3). what is the circumference of the circle?

Angelina_Jolie [31]

Well if it is touching the x-axis, the radius is 3 units.
C = 2 * pi * r = (2)(3.14)(3) = 18.8 or so

6 0

2 years ago

In △ABC, AB = 13.2m,

luda_lava [24]

Answer:

(i) ∠ABH = 14.5°

(ii) The length of AH = 4.6 m

Step-by-step explanation:

To solve the problem, we will follow the steps below;

(i)Finding ∠ABH

first lets find <HBC

<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)

46° + <HBC + 90 = 180°

<HBC+ 136° = 180°

subtract 136 from both-side of the equation

<HBC+ 136° - 136° = 180° -136°

<HBC = 44°

lets find <ABC

To do that, we need to first find <BAC

Using the sine rule

$\frac{sin A}{a}$ = $\frac{sin C}{c}$

A = ?

a=6.9

C=90

c=13.2

$\frac{sin A}{6.9}$ = $\frac{sin 90}{13.2}$

sin A = 6.9 sin 90 /13.2

sinA = 0.522727

A = sin⁻¹ ( 0.522727)

A ≈ 31.5 °

<BAC = 31.5°

<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)

31.5° +<ABC + 90° = 180°

<ABC + 121.5° = 180°

subtract 121.5° from both-side of the equation

<ABC + 121.5° - 121.5° = 180° - 121.5°

<ABC = 58.5°

<ABH = <ABC - <HBC

=58.5° - 44°

=14.5°

∠ABH = 14.5°

(ii) Finding the length of AH

To find length AH, we need to first find ∠AHB

<AHB + <BHC = 180° ( angle on a straight line)

<AHB + 46° = 180°

subtract 46° from both-side of the equation

<AHB + 46°- 46° = 180° - 46°

<AHB = 134°

Using sine rule,

$\frac{sin 134}{13.2}$ = $\frac{sin 14.5}{AH}$

AH = 13.2 sin 14.5 / sin 134

AH≈4.6 m

length AH = 4.6 m

8 0

2 years ago

What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def

Misha Larkins [42]

The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)

Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.

8 0

2 years ago

Equation <img src="https://tex.z-dn.net/?f=%28z%20%2B%20%20%5Cfrac%7B6%7D%7B7%7D%20%29%20%2B%20%20%5Cfrac%7B2%7D%7B14%7D%20%2

ddd [48]

Given:

The equation is

$\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1$