We have been given that function
is a transformation of the quadratic parent function
. We are asked to find the y-intercept of function g.
We know that the function
is an upward opening parabola with vertex at point (0,0).
We know that vertex form of a parabola is in form
, where point (h,k) represents vertex of parabola.
We can rewrite g(x) as:

The vertex of the function g(x) is at point (0,2).
We know that the vertex of a function is the point, when x is equal to 0. Therefore, the y-intercept of the g is at (0,2).
Endpoint T would be at the coordinates (4, -11)
X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0

for 1y^2+5y-3.36




y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6
It will just be a+b-180 because there are no like terms to put together :)