Hey there!
<span>Here are the steps involved:
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1.Change 65% into a decimal. Move the decimal two places to the left and you get 0.65.
2. Multiply 0.65 by 50.
<span>140 x 0.65 = 91.
3. Since you are decreasing 140 by 65%, subtract 140 by 91.
140-91= 49
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Answer:i cant see the hole question
Step-by-step explanation:
2x-1.1/4+x/3=2
2x-1/4+x/3=2
2x-1/4+x/3+1/4=2+1/4
2x+x/3=9/4
3(2x+x/3)=3.94
7x=27/4
7x/7=27/4/7
x=27/8
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Answer:
El área del cuadrado es de 3 centímetros cuadrados.
Step-by-step explanation:
Dado que se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura, para calcular el área del cuadrado se debe realizar el siguiente cálculo:
Radio = diámetro / 2
3 = X/2
X = 6
Hipotenusa del triángulo interno: 6 cm
Aplicando teorema pitagórico: lado al cuadrado mas lado al cuadrado es igual a hipotenusa al cuadrado.
L^2 + L^2 = 6
2L^2 = 6
L^2 = 6/2
L = √ 3
L = 1.732
Área de un cuadrado = L x L = L^2 = 3
Por lo tanto, el área del cuadrado es de 3 centímetros cuadrados.
Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1
