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SVEN [57.7K]
2 years ago
14

ILL GIVE BRAINLIEST.

Mathematics
2 answers:
Yakvenalex [24]2 years ago
8 0

Answer: This is a negative graph and it is proportional because it goes through the origin.

Step-by-step explanation:

Just beacause it goes through the origin does not mean it will be positive nor negative, if the line goes from the top left of the grid slanted down, it is negative. If the line goes from the top right of the graph slanted down, it is positive. It is proportional because it is a straight line that goes through the origin.

OLEGan [10]2 years ago
7 0

Answer:Under↓↓↓

Step-by-step explanation:

Ok so in this case it's a negative slope, because the line is going from left to right.

If the line was going form right to left then It would be a positive slope.

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If anyone can help me with these problems I will marry u seriously plz
belka [17]
27: C  28: B  29. A

And I kindly decline the marriage offer lol. If you need an explanation of how I did this then I will gladly do so they are pretty simple.
8 0
3 years ago
17 points if you know. Help please
vovangra [49]

Answer:

Step-by-step explanation:

Angles 153 and QRP are straight angles, and thus Angle QRP is

180 - 153, or 27 degrees.

The interior angles of the triangle must sum up to 180 degrees:

27 + (3y + 5) + (2y - 7) = 180.

combining like terms, we get:

5y - 25 = 180, or 5y = 155, or y = 31

Then Angle Q is 3(31) + 5, or 93

Angle P is 2(31) - 7, or 55, and

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6 0
3 years ago
Find the length of the segment AB.
ad-work [718]

Answer:

8.6

Step-by-step explanation:

You need to use the Patagorean theorem! :) Just do seven squared and five squared add them up and then square root them!!

3 0
2 years ago
Read 2 more answers
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
Help me on this question..........
aleksandrvk [35]
Answer: $18





Explanation: 6x3



7 0
3 years ago
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