Question

Henry has 3 black shirts and 7 blue shirts in his wardrobe. Two shirts are drawn without replacement from the wardrobe. What is the probability that both of the shirts are black?

Answer 1

Since there are three black shirts and 7 blue shirts, he has a 3/10 chance of picking a black.

Answer 2

Answer:

The probability that both of the shirts are black is $\frac{1}{15}$

Step-by-step explanation:

Given : Henry has 3 black shirts and 7 blue shirts in his wardrobe. Two shirts are drawn without replacement from the wardrobe.

To find : What is the probability that both of the shirts are black?

Solution :

Number of black shirts = 3

Number of blue shirt = 7

Total number shirts = 3+7=10

The probability that first shirts is black is $\frac{3}{10}$

Two shirts are drawn without replacement from the wardrobe.

Number of black shirt left = 2

Total shirts = 9

The probability that second shirts is black is $\frac{2}{9}$

So, The probability that both of the shirts are black is

$P=\frac{3}{10}\times\frac{2}{9}$

$P=\frac{6}{90}$

$P=\frac{1}{15}$