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Katena32 [7]
3 years ago
15

Scale factor and dilation 4/5

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

kinda need more info bRuH

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What Is The Prime Factor Of 4275 ?
jarptica [38.1K]

Answer:

5^2·3^2·19

Step-by-step explanation:

Well to find the prime factor we make the prime factorization tree.

Look at the image below↓

<em>Thus,</em>

<em>the prime factorization of 4275 is </em>5^2·3^2·19

<em>Hope this helps :)</em>

4 0
3 years ago
(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

6 0
2 years ago
Solve for b…………………..
Rasek [7]

Answer:

6mm

Step-by-step explanation:

B is x.

15 IS HYPOTENUS.

Therefore b is15-9

4 0
2 years ago
Read 2 more answers
Find BC round to the nearest tenth
slega [8]

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, c^2=a^2+b^2-2abcos\theta

We the plug in values: (CB)^2+6^2+5^2-2*6*5*cos74

and solve that CB is around 6.7

3 0
3 years ago
During strenuous work a human body generates about 2,400 BTUs of body heat per hour. If 7 bodybuilders are in a gym that is 20 f
Vlad [161]
The answer is b) 8.4
3 0
3 years ago
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