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allsm [11]
4 years ago
10

An atom is a small unit of matter. A small atom measures about 0.0000000001 meter. Express the decimal as a power of 10

Mathematics
1 answer:
blsea [12.9K]4 years ago
8 0
1x10^-10 That's the answer I bealieve
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What is the range of the function f(x)=3x-12 for the domain (-2,2)
MrRa [10]

-18

Step-by-step explanation:

F(x)=3x-12

F(-2)=3x-2-12

=-6-12

=-18

3 0
2 years ago
Please help with this question
Artemon [7]

Answer:

C.

Step-by-step explanation:

G(x) exceeds f(x) from x = 0 to x = 3.

Then we see that f(x) is 11  at x = 4 and g(x) is 10 at x = 4, so there is an intersection between these 2 points.

After this f(x) far exceeds g(x).

5 0
3 years ago
Can someone help me and tell me where it’s located at I will mark u brilliant
vodomira [7]

Answer: You can do this!

Step-by-step explanation: For D. The x= -1 and the y= 1 for E same thing the x= 7 and the y= 1 so look for the 7 on the x-axes and the one on the y-axes get it. I believe that you got this!

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8 0
3 years ago
A medicine is decaying at a rate of 5% per hour. If there were initially 1000mg of the medicine, how much is left after 4 hours?
Stolb23 [73]

Answer:

  814.5 mg remain after 4 hours

Step-by-step explanation:

The multiplier of the original quantity is 1 -5% = 0.95 for each passing hour. The amount remaining after x hours is ...

  y = 1000·0.95^x

For x=4, the amount remaining is ...

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8 0
3 years ago
Find the value of each variable.​
insens350 [35]

Step-by-step explanation:

11)

x= 5

{y}^{2}  = 2 \times  {5}^{2}  \\  {y}^{2}  = 50 \\ y = 5 \sqrt{2}

12)

\tan(30 )  =  \frac{9}{y}  \\ y =  \frac{9}{ \tan(30) }  = 9 \sqrt{3}  \\  {x}^{2}  =  {9}^{2}  +  {(9 \sqrt{3} )}^{2}  \\  {x}^{2}  = 324 \\ x = 18

13)

\sin(60)  =  \frac{x}{22}  \\ x = 11 \sqrt{3}  \\  \cos(60)  =  \frac{y}{22}  \\ y = 11

14)

{16}^{2}  =  {x}^{2}  +  {y}^{2}  \\ x = y \\  {16}^{2}  = 2 {x}^{2}  \\ x = 8 \sqrt{2}  \\ y = 8 \sqrt{2}

15)

\tan(30)  =  \frac{x}{42}  \\ x = 14 \sqrt{3}  \\   \cos(30)  = \frac{42}{y}  \\ y =  \frac{42}{ \cos(30) }  \\ y = 28 \sqrt{3}

16)

{(19 \sqrt{2}) }^{2}  =  {x}^{2}  +  {y}^{2}  \\ x = y \\ 722 = 2 {x}^{2}  \\  {x}^{2}  = 361 \\ x = 19 \\ y = 19

4 0
3 years ago
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