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kiruha [24]
3 years ago
11

Graph the equation using the slope and y-intercept y = -x + 3

Mathematics
2 answers:
UNO [17]3 years ago
5 0

Answer:

I got you

Step-by-step explanation:

Ulleksa [173]3 years ago
3 0

Answer:

<h3>Explained Below:</h3><h3 />

Step-by-step explanation:

Your y-intercept is a positive three, so your starting point would start on positive three on the y-axis. Since your slope is a negative one, your line should be heading towards the bottom right corner (much like your last question).

To find the next point on the graph, you need to go down one and over one. Or, one space.

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A right rectangular prism has a length of 8 ft, width of 8 1/4 ft, and height of 4 1/2 ft. What is the volume of the prism?
Dahasolnce [82]

<u>Answer:</u>

297 cubic feet

<u>Step-by-step explanation:</u>

We are given that a right rectangular prism has a length of 8 ft, width of 8 1/4 ft, and height of 4 1/2 ft.

We are to find the volume of this prism.

We know the formula of volume of a rectangular prism is given by: w \times h \times l

where w is the width,  h is the height and  l is the length of the prism.

So substituting the given values in the formula:

Volume of prism = 8\frac{1}{4} \times 4\frac{1}{2} \times 8 = 297 cubic feet

8 0
3 years ago
Read 2 more answers
2 and 3? I need help please
marishachu [46]

Answer:

2: 7:10 3: 6:14

Step-by-step explanation:

There are 7 blue marbles and 10 are green

There are 6 circles and 14 hearts

7 0
3 years ago
What is the name of the shape graphed by the function r^2=9 cos(2 theta)?
Lady bird [3.3K]

<span>The name of the shape graphed by the function r ^ 2 = 9 cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a plane curve with a feature shape which consists of two loops that meet at a central point. The curve is also sometimes called as the lemniscate of Bernoulli. </span>


Explanation:

The period of coskθ is 2π/k. In this case, k = 2 therefore the period is π.

r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily one period can be chosen as θ ∈ [0, π] wherein cos 2θ ≥0.

As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.

Also, as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the vertical θ = π/2

A Table for half period [0,π4/] is adequate for the shape in Quarter1

Use symmetry for the other three quarters:

(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>

5 0
3 years ago
Solve for k.<br> 6 1<br> 2k - 6 - 3
Taya2010 [7]

Answer:

k = 6.

Step-by-step explanation:

k = 6

2k = 12

12 - 6 - 3 = 3

k = 1

2k = 2

2 - 6 - 3 = -7

So, the answer is k = 6 because it makes more sense.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=6%20%5Cdiv%207.74%20%3D%20" id="TexFormula1" title="6 \div 7.74 = " alt="6 \div 7.74 = " align
Liula [17]
6 \div 7.74 = \dfrac{6}{7.74}=\dfrac{6\cdot100}{7.74\cdot100}=\dfrac{600}{774}=\dfrac{600:2}{774:2}=\dfrac{300:3}{387:3}=\dfrac{100}{129}
4 0
3 years ago
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