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Mariana [72]
3 years ago
6

Help..?................

Mathematics
1 answer:
ad-work [718]3 years ago
8 0
The answer is: 
____________________________________________
[A]: Erin Naismith lives in Springfield, Massachusetts.
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Dan earns $9.50 per hour as a dishwasher. Determine the fewest number of hours he must work to earn
Oksana_A [137]

Answer:

43 hours

Step-by-step explanation:

\frac{y}{1} :\frac{408}{9.5}

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

y=42\frac{18}{19}

43 hours

8 0
3 years ago
Read 2 more answers
-12 times 1over3 help.
sergey [27]

Answer:

-4

Step-by-step explanation:

4 0
3 years ago
Please help me with this math question
spayn [35]
Y=1/9(-1)+4

Explanation:
X=-1 and y=8
6 0
3 years ago
find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be
olasank [31]
Hello,

u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
if\ q=2 \ then\  \sum_{i=0}^{8}\ 4*(2)^i= 4*\dfrac{1-2^9}{1-2} =2044\\

if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\





Answer B (but see the problem)
7 0
3 years ago
Read 2 more answers
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
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