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Tju [1.3M]
3 years ago
13

If the discriminant of an equation is zero, which of the following is true of the equation?​

Mathematics
2 answers:
White raven [17]3 years ago
7 0

\sf Your \: question \: is \: incomplete. \:

______________________

\sf \: I \: believe \: this \: is \: the \: answer \: you \: wanted ⟹

\sf If  \: the  \: discriminant  \: of \:  an \:  equation \:  is  \: zero, \: then \\  \sf \: the \: equation \: will \: have \:\underline{ 1 \: real \: solution \: with \: real \: and \: equal \: roots}.

\boxed{ \sf{Explanation}}

\sf If \: discriminant \: of \: quadratic \: equation  \: ax^{2} + bx + c \: \\ \sf is \: b^{2} - 4ac = 0 \: then \: it \: will \: have \\ \sf↦\underline{1 \: real \: solution \: with \: real \: and \: equal \: roots.}

Nadya [2.5K]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

If b² - 4ac = 0

Then the roots are real and equal

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Solve the equation by the Quadratic Formula. x^2+3=9x
Nadya [2.5K]

Answer:

Step-by-step explanation:

Rearrange the given x^2+3=9x in standard quadratic form:

1x^2 - 9x +3 = 0

Then the three coefficients are a = 1, b = -9 and c = 3.

The discriminant is √(b^2 - 4ac), or √(81 - [1][3]), or √78.

                                        ± √78

Thus, the roots are x = ----------------

                                               2

5 0
3 years ago
Read 2 more answers
1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )
sergeinik [125]
Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are \frac{10!}{(10-6)!6!} ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are \frac{7!}{(7-1)!1!} ways of choosing the first winner, which is 7 ways
There are \frac{6!}{(6-1)!1!} ways of choosing the second winner, which is 6 ways
There are \frac{5!}{(5-1)!1!} ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is \frac{15}{31}×\frac{9}{30}, which equals to \frac{9}{62}

The probability of eating two green candies is \frac{7}{31}×\frac{6}{30} which equals to \frac{7}{155}
3 0
3 years ago
Please help me find x.
aleksklad [387]
Multiply 10 times 5 then divide it by 4

3 0
3 years ago
Read 2 more answers
Can somebody help me & explain ​
Ganezh [65]

Answer:

Step-by-step explanation:

D because it shows that 1x1/3 is shown on # D

5 0
3 years ago
Evaluate the expression when a= 6 and c= -6. -a+9c​
Troyanec [42]

Answer:

=-a +9c

=-6+9×-6

=-6+(-54)

=-6-54

=-60

hope it helps you!!!

stay safe healthy and happy!!!!

7 0
3 years ago
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