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konstantin123 [22]
4 years ago
14

The triangles shown are congruent which of the following must be true

Mathematics
1 answer:
Fantom [35]4 years ago
7 0
The bottom answer m y = m h
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A white-tailed deer can sprint at speeds up to 30miles per hour . American bison can run at speeds up to 3,520feet per minute. W
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Answer:

The Bison is faster by 10 mph.

In 1 minute, the bison runs 3, 520 feet .

In 60 minutes, the bison would run  3520*60 feet  = 211, 200 feet per hour.

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3 years ago
the height of a triangle is 7 cm longer than its base. The area of the triangle is 60 cm². What is the base of the triangle?
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Base is 8cm, and height is 15 cm
4 0
3 years ago
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Eduardo used fabric to make three costumes. he used 1/4 yard for first then 2/4 yard for the second and 3/4 yard for the third c
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 add the fractiosn together, since they all have the same denominator, simply add the numerators
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6 0
4 years ago
Please help me someone
Brut [27]

Answer: C

Step-by-step explanation: Consider a triangle with points A, B and C. You must create a perpendicular bisector of AB and then a perpendicular bisector of BC that crosses each other. Then you must label the center of that point D, and then using a compass tool, create a circle around the triangle.

8 0
2 years ago
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What are the potential solutions of log4x+log4(x+6)=2?
lions [1.4K]

The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
  • Power Rule for Logarithms - log_{b}(a^c)=c*log_{b}a

The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0
2 years ago
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