What are the values of the trigonometric ratios for this triangle?

Mathematics

1 answer:

Zigmanuir [339]3 years ago

3 0

Answer:

sin© = 3/5

Cos© = 4/5

Tan© = 3/4

Explanation:

The opposite (opp) side of the right angle triangle is the side facing the angle ©

The hypothenus (hyp) side is the longest side,

The adjacent (adj) side is the third side.

sin© = opp/hyp

Cos© = adj/hyp

Tan© = opp/adj

You might be interested in

Use your knowledge of similar triangles to explain why the construction in the image divides the line segment into equal parts.

strojnjashka [21]

Answer:

This image show how to divide a given line segment into a number of equal parts by using a compass and ruler. First, draw the line AB. Secondly, draw a line above and divide into 5 equal distances to make a line AC. Third, using a compass by getting the distance of point C and B to be equal in the distance of point A and D, also getting the distance of point C to A to be equal to point B and D, then to make the Line DB. Finally divide into 5 equal parts by compass.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help pls it’s due soon make sure to follow the steps I don’t get it

amm1812

The final answer that i got from this was -x-13

6 0

2 years ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$