Step-by-step explanation:
<h3><u>✞︎</u><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u></h3>
5(3-x)+1=3(x+4)
<h3><u>✞︎</u><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u></h3>
<u>S</u><u>o</u><u>l</u><u>v</u><u>e</u><u> </u><u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u>
<h3><u>✞︎</u><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u></h3>
![\tt\large\underline{15-5x+1=3x+12}](https://tex.z-dn.net/?f=%5Ctt%5Clarge%5Cunderline%7B15-5x%2B1%3D3x%2B12%7D)
![\large{✰} \bf \underline\color{purple}{16-5x=3x+12}](https://tex.z-dn.net/?f=%5Clarge%7B%E2%9C%B0%7D%20%5Cbf%20%5Cunderline%5Ccolor%7Bpurple%7D%7B16-5x%3D3x%2B12%7D)
![\tt\large\underline{\longmapsto16-12-3x+5x}](https://tex.z-dn.net/?f=%5Ctt%5Clarge%5Cunderline%7B%5Clongmapsto16-12-3x%2B5x%7D)
![\tt\large\underline{\longmapsto4-8x}](https://tex.z-dn.net/?f=%5Ctt%5Clarge%5Cunderline%7B%5Clongmapsto4-8x%7D)
![\tt\large\underline{\longmapsto8x=4}](https://tex.z-dn.net/?f=%5Ctt%5Clarge%5Cunderline%7B%5Clongmapsto8x%3D4%7D)
![X=\longmapsto\sf \dfrac{\cancel{4}}{\cancel{8}}](https://tex.z-dn.net/?f=X%3D%5Clongmapsto%5Csf%20%5Cdfrac%7B%5Ccancel%7B4%7D%7D%7B%5Ccancel%7B8%7D%7D)
![\tt\large\underline{\longmapsto \: \: \: \: x = \frac{1}{2} }](https://tex.z-dn.net/?f=%5Ctt%5Clarge%5Cunderline%7B%5Clongmapsto%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20x%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%7D)
Answer:
The GCF of 18 and 176 is 2
Step-by-step explanation:
To get the Greatest Common Factor (GCF) of 18 and 176 we need to factor each value first and then we choose all the copies of factors and multiply them:
18: 2 × 3 × 3
176: 2 × 2 × 2 × 2 × 11
GCF: 2
The Greatest Common Factor (GCF) is: 2
( the greatest common factor of 8 and 176 is 8 btw if anyone wanted to know. the author meant to say " of 18 and 176 ", not "of 8 and 176"... they said it in the comments of the question :] )
Answer:
x = 10
PQ = 27
QR = 20
Step-by-step explanation:
You can add up PQ and QR and set it equal to PR. Solve for x.
(2x + 7) + (2x) = 47
2x + 7 + 2x = 47
4x + 7 = 47
(4x + 7) - 7 = 47 - 7
4x = 40
4x/4 = 40/4
x = 10
Now, use the solved x-value to find PQ and QR.
PQ = 2x + 7
PQ = 2(10) + 7
PQ = 20 + 7
PQ = 27
QR = 2x
QR = 2(10)
QR = 20
Answer:
1^-1 = 1/1^1 = 1
Step-by-step explanation:
In fact, 1^345 = 1 and 1^-345 = 1
Zero to any power is 0.
1 to any power is 1