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sveticcg [70]
3 years ago
14

9. You have a record of your age x (in years) and your height y (in inches) on

Mathematics
2 answers:
Kay [80]3 years ago
8 0
The y’s can be a duplicate
Rashid [163]3 years ago
7 0

Answer:

Step-by-step explanation:

The y's can be a duplicate and g(x) can still be a function. Since travelling back in time is not possible, all most all ages along the x axis will produce a function as long as x>0.

It doesn't have to be much over 0 to start counting it. As soon as birth occurs height can be measured and usually is.

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Need help with this math question
olga_2 [115]

The correlation coefficient is -0.87; strong correlation

<h3>How to determine the correlation coefficient?</h3>

The given parameters are:

x = Time spent working out

y = lbs Overweight

Next, we enter the table of values in a graphing tool.

From the graphing tool, we have the following summary:

<u>X Values</u>

  • ∑ = 27.1
  • Mean = 2.71
  • ∑(X - Mx)2 = SSx = 22.569

<u>Y Values</u>

  • ∑ = 89
  • Mean = 8.9
  • ∑(Y - My)2 = SSy = 778.9

<u>X and Y Combined</u>

  • N = 10
  • ∑(X - Mx)(Y - My) = -114.19

<u>R Calculation</u>

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

r = -114.19 / √((22.569)(778.9))

r = -0.8613

Approximate

r = -0.87

This means that the correlation coefficient is -0.87

Also, the correlation coefficient is a strong correlation, because it is closer to -1 than it is to 0

Read more about correlation coefficient at:

brainly.com/question/27226153

#SPJ1

6 0
2 years ago
In an auditorium, 1/6 of the students are 5th Graders, 1/3 are 4th Graders, and 1/4 of the remaining students are 2nd graders. I
avanturin [10]
1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
5 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
What are the zero(s) of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E%7B2%7D-36x%20%7D%7Bx-9%7D" id="TexFo
Contact [7]

Answer:

D

Step-by-step explanation:

The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:

0 = 4 {x}^{2}  - 36x

I will use the quadratic formula:

\frac{ 36  +  \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{  36 + 36}{8}  = 9

Therefore, x = 9 is a 0. Let's check with subtracted root now:

\frac{ 36   -    \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{ 36  -  36}{8}  =  0

It appears 0 is also a root.

Therefore, the answer is D.

7 0
3 years ago
Round each number to the underlined place. <br> 4.6666<br> The third 6 is underlined
Nadya [2.5K]
Hello There!

It would be 4.667.

Hope This Helps You!
Good Luck :)
3 0
3 years ago
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