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svetoff [14.1K]
2 years ago
6

Apply the distributive property to factor out the greatest common factor of all three terms. {10a - 25 + 5b} =10a−25+5b =

Mathematics
1 answer:
Rom4ik [11]2 years ago
8 0

Answer:

5(2a -5 + b)

Step-by-step explanation:

(10a - 25 + 5b) = 5( 2a - 5 + b)

5(b +  2a  - 5) = 5(2a - 5 + b)

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What is the slope of the line on the graph need answer ASAP please thank you I'm in k-12​
Rina8888 [55]
The answer is -1 your welcome
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2 years ago
Diamonds have a density of 3.5 LaTeX: \frac{g}{cm^3}g c m 3. How big is a diamond that has a mass of 0.10 g?
liubo4ka [24]

For this case we have that by definition, the density is given by:

d = \frac {M} {V}

Where:

M: It is the mass of the diamond

V: It is the volume of the diamond

According to the data of the statement we have:

d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g

So the volume is:

V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3

Thus, the volume of the diamond is approximately 0.03 \ cm ^ 3

Answer:

0.03 \ cm ^ 3

3 0
3 years ago
95 - 4G < 40 + 5G plz help me
7nadin3 [17]

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5 0
2 years ago
A spheres radius is multiplied by 2. How is it’s surface area affected
dexar [7]

Answer:

The surface area is multiplied by 3.

Step-by-step explanation:

If r is the radius of a sphere its surface area = 4(pi)r^2. If the radius is doubled then its surface area = 4(pi)(2r)^2 = 4*4(pi)r^2. So the surface area becomes 4-fold or the increase in surface area is 300%.

3 0
3 years ago
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.35°F and a standard deviati
DochEvi [55]

Answer:

a) 99.97%

b) 65%

Step-by-step explanation:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 98.35°F and a standard deviation of 0.64°F.

a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?

μ - 3σ

98.35 - 3(0.64)

= 96.43°F

μ + 3σ.

98.35 + 3(0.64)

= 100.27°F

The approximate percentage of healthy adults with body temperatures is 99.97%

b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?

within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

98.35 - (0.64)

= 97.71°F

μ + σ.

98.35 + (0.64)

= 98.99°F

Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%

4 0
3 years ago
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