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topjm [15]
3 years ago
8

What is the solution to the system of equations graphed below?

Mathematics
2 answers:
zepelin [54]3 years ago
8 0
<span>y = 4x + 11 
y = -2x - 1 

4x + 11 = -2x - 1
4x + 2x = -1 - 11
6x = -12
x = -12/6
x = -2

</span>y = 4x + 11 
y = 4(-2) + 11 
y = -8 + 11 
y=3

<span>A. (-2,3)</span>
Crazy boy [7]3 years ago
4 0

Answer:

Option A. (-2, 3)

Step-by-step explanation:

The given equations graphed are Y = 4x + 11 and Y = -2x - 1

Now for the solution to the system of equations graphed Y values will be the same or a point where these lines intersect will be the solution.

Y = 4x + 11 = -2x - 1

4x + 2x = -1 - 11

6x = -12

x = -2

Now by putting x = -2 in the first equation.

Y = 4.(-2) + 11 = -8 + 11 = 3

The common point will be (-2, 3)

Therefore option A. (-2, 3) will be the answer.

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This 8 inches is the diameter of the cylinder formed by the rotation. 
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6 0
3 years ago
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3 years ago
What is the length of line segment PQ? If you can please explain, thanks.
nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

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