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marissa [1.9K]
3 years ago
13

Find missing term w+9/6=12​

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

W+9/6=12

9/6=1.5

1.5 + 12=13.5

I believe 13.5 is the answer correct me if I’m wrong

Hope this helps
Sladkaya [172]3 years ago
3 0

Answer: The missing term for W is 10.5.

Step-by-step explanation:

W + 9/6 = 12

W +9/6 - 9/6 = 12- 9/6

W = 12 - 1.5

W = 10.5

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A=6 cm,b=9cm,and c =3 cm
Crazy boy [7]
The lengths of sides a and c add to 9 cm, the length of side b.
In a triangle, the the sum of the lengths of any two sides must be greater than the the length of the third side. These dimensions do not make a triangle.

Is this really what you meant? Why did you use capital A for a side? Or is A an angle, and it measures 6 deg, not 6 cm?
4 0
3 years ago
Multiply (x^2+4x+2) (2x^2+3x-4)
algol13

Answer:

(x² + 4x + 2)(2x² + 3x - 4) equals 2x⁴ + 11x³ + 12x² - 10x - 8

Step-by-step explanation:

<em>(x² + 4x + 2)(2x² + 3x - 4)</em>

Multiply each term in the first parentheses into the expression in the second parentheses.

<em>2x⁴ + 3x³ - 4x² + 8x³ + 12x² - 16x + 4x² + 6x - 8</em>

Combine like terms.

<em>2x⁴ + 11x³ + 12x² - 10x - 8</em>

So, your answer would be letter choice B.

<em />

6 0
3 years ago
Read 2 more answers
A group of employees is stranded on top of a 120 feet building because a fire occurred. Your goal is to throw a rope from a 60 f
Paul [167]

Step-by-step explanation:

-16t² + 64t + 60 = 120

this is a quadratic equation, and its points of f(t) = 0 can be calculated. there are usual 2 such solutions for a quadratic equation.

so, we need to bring it to a form that ends in "= 0".

-16t² + 64t - 60 = 0

that is also the same as

-4t² + 16t - 15 = 0

the formula for the solutions of such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

a = -4

b = 16

c = -15

so,

t = (-16 ± sqrt(256 - 4×-4×-15))/(2×-4) =

= (-16 ± sqrt(256 - 240))/-8 =

= (-16 ± sqrt(16))/-8 = (-16 ± 4)/-8

t1 = (-16 + 4)/-8 = -12/-8 = 3/2

t2 = (-16 - 4)/-8 = -20/-8 = 5/2

so, it depends on what the unit of time t is. let's assume seconds.

therefore, the rope will reach the top of the building while going up after 3/2 = 1 1/2 = 1.5 seconds.

and then, as the shot rope makes a curve and comes back down again (that is why we have 2 solutions : the rope will reach the height of 120ft during its flight path twice : once while still going up, and once when coming back down again) it will be at the height of the top of the building after 5/2 = 2 1/2 = 2.5 seconds.

so, it depends if the people there can grab it at the first chance, and if the path of the rope would allow them to grab it also again on its way back down. this we don't know.

I therefore guess, that your teacher is aiming for the first solution.

4 0
3 years ago
A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The
disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ±  5.09

=-2.09, 8.09  is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0
3 years ago
I NEED HELP WITH THIS ASAP
grin007 [14]
hopefully someone helps u with this tho sorry
3 0
2 years ago
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