Question

What is the solution to the system of linear equations? {2x+4y=203x+2y=26 enter your answer in the boxes. ( , )?

Answer 1

(3,4) is the answer, with x=3 and y=4

Answer 2

Answer:

$(8,1)$

Step-by-step explanation:

We have been given a system of linear equations:

$2x+4y=20...(1)$

$3x+2y=26...(2)$

We will use substitution method to solve linear equation. From equation (1) we will get,

$x=\frac{20-4y}{2}$

Substituting this value in equation (2) we will get,

$3*\frac{20-4y}{2}+2y=26$

$\frac{60-12y}{2}+2y=26$

Let us have a common denominator.

$\frac{60-12y}{2}+\frac{2*2y}{2}=26$

$\frac{60-12y}{2}+\frac{4y}{2}=26$

$\frac{60-12y+4y}{2}=26$

$\frac{60-8y}{2}=26$

$\frac{60-8y}{2}*2=26*2$

$60-8y=52$

$60-60-8y=52-60$

$-8y=-8$

Upon dividing both sides by $-8$ we will get,

$\frac{-8y}{-8}=\frac{-8}{-8}$

$y=1$

Upon substituting $y=1$ in equation (1) we will get,

$2x+4*1=20$

$2x+4=20$

$2x+4-4=20-4$

$2x=16$

Upon dividing both sides of the equation by 2 we will get,

$\frac{2x}{2}=\frac{16}{2}$

$x=8$

Therefore, the solution of our given system of equations is $(8,1)$.