Let that be
Two vertical asymptotes at -1 and 0
If we simply
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is
Graph attached
Answer: 164
Step-by-step explanation: 656
/4
164
What you can do in this case is the following rule of three to find the result:
1 light year ---> 5.88 * 10 ^ 12 miles
3.2 * 10 ^ 2 light year ---> x
Clearing x we have:
x = ((3.2 * 10 ^ 2) / (1)) * (5.88 * 10 ^ 12)
x = 1.88 * 10 ^ 15 miles
answer:
In scientific notation, approximately it is 1.88 * 10 ^ 15 miles
Answer:
23
Step-by-step explanation:
All triangles = 180 degrees
65 + 4x + x = 180
65 + 5x = 180
- 65 - 65
----------------------
5x = 115
--- = ----
5 = 5
x = 23
4(23) = 92
F = x = 23
B> 65
92 + 23 + 65 = 180
x = 23
F> = B>
Answer:
greater than 16 and less than 25(easy)
