3 hours and 10 minutes hope this helps :D
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that
. Then, the normal probability density function for the random variable X is given by
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
I can not see your ferris wheel and so I can not answer it.
D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30
0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters
d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes
Answer:
B
Step-by-step explanation:
the one on the tight becasue try plugging in zero