PLS HELP ME!!!!!!! I REALLY NEED THIS!!!!!!!

Mathematics

1 answer:

Sliva [168]2 years ago

3 0

Answer:

ask your teacher

Step-by-step explanation:

ask your teacher

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HELP WILL GIVE BRANLIEST! WILL RATE! AND SAY THANKS!!!

Drupady [299]

Answer:

9.57 inch

Step-by-step explanation:

(4/3)×pi×8³ = 14×16×h

h = (4/3)×pi×8³ ÷ (14×16)

h = 64pi/21 inch

Or, 9.57 inch (3 sf)

5 0

3 years ago

Pls help I don't know how to do this

AVprozaik [17]

Answer:

Vertex, I believe.

7 0

2 years ago

Solve the simultaneous equations 4x-3y=19 and 2x+3y=23

kogti [31]

The answer is x=7 and y=3

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2 years ago

Read 2 more answers

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$