v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
22.90*1.05=24.045
sales tax is 5% added to 100% of the original cost making the actaul cost including tax $24.045
Given that the First term of the Arithmetic sequence = -3
⇒ a = -3
We know that nth term of a Arithmetic sequence is : Tn = a + (n - 1)d
where a is the first term and d is the common difference
Given that 10th term is 15
⇒ T₁₀ = -3 + (10 - 1)d
⇒ -3 + (10 - 1)d = 15
⇒ 9d = 18
⇒ d = 2
⇒ Common difference of given Arithmetic Sequence is 2
Answer:
y=-5/3x+13.
Step-by-step explanation:
As a line that is perpendicular to anoher line has a slope that is the negative reciprocal of the line's original slope, we know that the slope of our new line is -5/3. As it passes point (12, -7), we can use the point slope formula which is y-y1=m(x-x1). So plug in, y+7=-5/3(x-12) and that gives us y+7=-5/3x+20 which gives our final answer of y=-5/3x+13.
Answer:
Yes
Step-by-step explanation:
The difference of 18 and 3 is 15 which can be expressed as fraction, so its a rational number.
