Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
Answer:
a
Step-by-step explanation:
if it -4 or 4 it would be undefined
Answer:
18245
Step-by-step explanation:
We have to use L.C.M,
L.C.M(20,24,32,38)
2|20,24,32,38
2| 10 ,12 ,16 ,19
2| 5 , 6 , 8 , 19
2| 5 , 3 , 4 , 19
2| 5 , 3 , 2 , 19
L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19
= 18240
Now for each case remainder is 5,
So the number is 18240+5
=> 18245
Answer:
its the 3rd one
Step-by-step explanation:
Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude
The solution of the first pair of equations is
(x, y) = (1.5, 0.9)
The solution of the first and last equations is
(x, y) = (-0.9, -1.5)
The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.