Which change will quadruple the lateral surface area of a cone?

Mathematics

2 answers:

olasank [31]3 years ago

7 0

Answer:

D)Increase the height so that the slant height quadruples.

Step-by-step explanation:

Given that a cone undergoes changes in height or radius or slant height.

We have to find which change will quadruple the lateral surface area of cone.

Lateral surface area of cone = $\pi r l$

Thus depends on radius and slant height

Let us check one by one options

A) When radius quadruples by increasing slant height we find lateral SA

will change more than quadruples because of change of slant height. Hence wrong.

B) When we quadruple the height 4 times, slant height will not be quadrupled exactly hence option is wrong.

C) If both radius and height are quadrupled then LSA will become 16 times the original hence false.

D) When we increase the height so that slant height quadruples, then radius will be the same, thus making LSA = 4 times the original

Option D is right.

vlada-n [284]3 years ago

6 0

Don't know try something else it will probably help

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Solve the following for the specified variable<br><br> Z=s/2(P+p); for P

lapo4ka [179]

Answer:

$\boxed{\sf P = \frac{2Z}{s} - p}$

Step-by-step explanation:

$\sf Solve \ for \ P: \\ \sf \implies Z = \frac{s}{2} (P + p) \\ \\ \sf Z = \frac{s}{2} (P + p) \ is \ equivalent \ to \ \frac{s}{2} (P + p) = Z: \\ \sf \implies \frac{s}{2} (P + p) = Z \\ \\ \sf Divide \ both \ sides \ by \ \frac{s}{2} : \\ \sf \implies P + p = \frac{2Z}{s} \\ \\ \sf Substrate \ p \ from \ both \ sides: \\ \sf \implies P = \frac{2Z}{s} - p$