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MatroZZZ [7]
3 years ago
7

Which change will quadruple the lateral surface area of a cone?

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

D)Increase the height so that the slant height quadruples.

Step-by-step explanation:

Given that a cone undergoes changes in height or radius or slant height.

We have to find which change will quadruple the lateral surface area of cone.

Lateral surface area of cone = \pi r l

Thus depends on radius and slant height

Let us check one by one options

A) When radius quadruples by increasing slant height we find lateral SA

will change more than quadruples because of change of slant height. Hence wrong.

B) When we quadruple the height 4 times, slant height will not be quadrupled exactly hence option is wrong.

C) If both radius and height are quadrupled then LSA will become 16 times the original hence false.

D) When we increase the height so that slant height quadruples, then radius will be the same, thus making LSA = 4 times the original

Option D is right.

vlada-n [284]3 years ago
6 0
Don't know try something else it will probably help
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Please help! Will mark Brainliest!
borishaifa [10]

Answer:

I wasnt able to put my answer to your current question after this so ill put my response here. If the answer was the first box then the other pair would be the third one. If the second box was the answer then the other pair would be the last one. This is a tough one indeed when you forgot how to do this lol. But based from my knowledge I would go with the 2nd and last one.

5 0
3 years ago
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Which logarithmic equation is equivalent to 82 = 64?
34kurt

Answer: Choice B

2 = \log_{8}(64)

======================================================

Explanation:

The original equation is 8^2 = 64 with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that \text{y} = b^{\text{x}} is equivalent to the log form of \text{x} = \log_{b}(\text{y}) where b is the base of each.

8 0
2 years ago
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I need help with this due in a few days.
viva [34]
1. 2^6.
2. 2^3.
3. 3^7
4. 6x^4
5. 4x^2
6. 12n^5
7. 9x^2
To find the answer of these questions, add the exponents. If there is whole numbers in the problem, you have to multiply the numbers. For number 7, do 3^2 and x^2. Hope this helps!
8 0
3 years ago
Solve for x . Round to the nearest tenth, if necessary.
Jet001 [13]

Answer:

x = 24.1

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 15 = x/90

90 tan 15 =x

x=24.11542

To the nearest tenth

x = 24.1

7 0
3 years ago
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Latitude and longitude describe locations on the Earth with respect to the equator and prime meridian. The table shows the latit
Vedmedyk [2.9K]

The temperature decreases by about 1.7° for each 1-degree increase north in latitude.

Given

Latitude and longitude describe locations on the Earth with respect to the equator and prime meridian.

The table shows the latitude and daily high temperatures on the first day of spring for different locations with the same longitude.

The first row is labeled latitude (degrees North) with entries 42, 45, 39, 35, 32, 41, 40, 33, 30.

The second row is labeled high temperature (degrees Fahrenheit) with entries 53, 51, 67, 63, 70, 58, 61, 67, 72.

<h3>What is the slope of the line?</h3>

The slope of a line in the two-dimensional Cartesian coordinate plane is usually represented by the letter m, and it is sometimes called the rate of change between two points.

  • Latitude and longitude are a system of lines used to describe the location of any place on Earth.

  • Lines of latitude run in an east-west direction across Earth.

  • Lines of longitude run in a north-south direction.

  • Although these are only imaginary lines, they appear on maps and globes as if they actually existed.

Hence, the temperature decreases by about 1.7° for each 1-degree increase north in latitude.

To know more about the Slope of the line click the link given below.

brainly.com/question/6317822

5 0
3 years ago
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