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ki77a [65]
3 years ago
11

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

ion of bees seems to be decreasing steadily at a rate of 5% per year. If the number of bees in the population after x years is represented by f(x), which statements about the situation are true? Check all that apply. The function f(x) = 9,000(1.05)x represents the situation. The function f(x) = 9,000(0.95)x represents the situation. After 2 years, the farmer can estimate that there will be about 8,120 bees remaining. After 4 years, the farmer can estimate that there will be about 1,800 bees remaining. The domain values, in the context of the situation, are limited to whole numbers. The range values, in the context of the situation, are limited to whole numbers.
Mathematics
2 answers:
MArishka [77]3 years ago
4 0

Answer:

B. The function f(x) = 9,000(0.95)x represents the situation.  

C. After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.  

F. The range values, in the context of the situation, are limited to whole numbers.

Step-by-step explanation:

Hope this helps!

grigory [225]3 years ago
3 0
<span>I think the answer is The function f(x) = 9,000(0.95)x </span>
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yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
If f(x) = -3x - 5 and g(x) = 4x - 2, find (f - g)(x).
ratelena [41]

Answer:

  A.  (f-g)(x) = -7x -3

Step-by-step explanation:

(f -g)(x) = f(x) -g(x) = (-3x -5) -(4x -2)

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3 0
2 years ago
20.35 - 08.57 - 09.99 ​
rewona [7]
Your answer will be 1.49
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2 years ago
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16 factory workers made 40 pieces in a certain amount of time. How many workers are needed to make (1) 20, (2)25 and (3)100 piec
lorasvet [3.4K]

1. 40 units___16 workers

20 units___x= 8 workers

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leonid [27]

Answer:

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Step-by-step explanation:

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Therefore, your answer is 3 2/6. In simplified terms, it would be 3 1/3.

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