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3 years ago

15

one half of the students are girls.One third of the girls have long hair. What fraction of the students are girls with long hair

? What percent of the students are girls with long hair?

1 answer:

Elenna [48]3 years ago

3 0

1/6 of the students have long hair.

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One angle is 25° bigger than another angle. the two angles are supplementary. what is the measure of the two angles

Rama09 [41]

1st angle - x⁰
2nd angle - (x+25)⁰
The angles are supplementary,
so
x+x+25=180
2x=155
x=77.5⁰ -1st angle

77.5+25=102.5⁰ - 2nd angle

3 0

3 years ago

How to find the area under the standard normal curve between z 1.5 and z 2.5?

alisha [4.7K]

It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z. The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore
P(Z<z2)-P(Z<z1).

For example, to find the area between z1=1.5, z2=2.5
is
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060

(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).

8 0

3 years ago

The domain and range in this graph will be:

Nataliya [291]

Answer:

a.

Step-by-step explanation:

this is a line going from -infinity to +infinity in x and in y direction.

for b or c to be right the function would have to be a single point, as nothing else is valid as value.

8 0

2 years ago

A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th

Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

$\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}$

Therefore;

$\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}$

Which gives;

$\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}$

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}$

Similarly, we can get;

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}$

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0

2 years ago

Evan was broke didn't he got his weekly allowance but because he has a hard time saving money he spent half his weekly allowance

grin007 [14]

Answer:

$16

Step-by-step explanation:

Let his weekly allowance = x

Amount spent playing golf = x / 2

Amount earned for cleaning car = $4

Final amount at hand = $12

Mathematically ;

x/2 + 4 = 12

x/2 = 12 - 4

x/2 = 8

x = 2 * 8

x = $16

Weekly allowance = $16

8 0

2 years ago