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Aleks [24]
3 years ago
6

Given the equation of the circle x2+6x+y2=7 use completing the square and factoring to write the equation in standard form

Mathematics
1 answer:
Kitty [74]3 years ago
8 0
<span>x2+6x+y2=7

We add 9 to each side of the equation
</span>
x2+6x+y2 + 9 =7 <span>+ 9</span>

(x+3)**2 + (y+0)**2 = 16

(x+3)**2 + (y+0)**2 = 4**2            (Standard form)


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the y intercept is 2

Step-by-step explanation:

we can see this because the line crossed the 2 on the y axis line

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A sidewalk is built 12 bricks wide by laying each brick side by side.how many inches wide is this sidewalk is each brick measure
yaroslaw [1]

To solve for the width simply multiply the two numbers:

width of sidewalk = 12 * (3 7/8)

 

Where 3 7/8 = 31/8

 

so calculating,

width of sidewalk = 12 * (31 / 8)

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I really need help with this question
DerKrebs [107]
I think its B ......
6 0
3 years ago
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

8 0
1 year ago
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