Question

. A random sample of 250 working adults found that 37% access the internet at work, 44% access the internet at home, and 21% access the internet at both work and home. What is the probability that a person in this sample accesses the internet at home or at work

Answer 1

Answer:

0.6 is the required probability.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 250

Probability of accessing internet at work = 37%

$P(W)=0.37$

Probability of accessing internet at home = 44%

$P(H)=0.44$

Probability of accessing internet at work and home = 21%

$P(W\cap H)=0.21$

We have to evaluate the probability that a person in this sample accesses the internet at home or at work.

$P(H\cup W) = P(H) + P(W) - P(W\cap H)\\P(W\cup H) = 0.37 + 0.44-0.21\\P(H\cup W) = 0.6$

Thus, 0.6 is the probability that a person in this sample accesses the internet at home or at work