Answer:
3 sqrt(3) =x
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj / hyp
cos 30 = x/6
6 cos 30 = x
6 ( sqrt(3)/2) = x
3 sqrt(3) =x
Answer:
the large box weight is 6.50 kg and the small box weight is 13.75 kg
Step-by-step explanation:
The computation of each type of box weight is as follows:
Let us assume the large box be x
And, the small box be y
So,
2x + 3y = 47.......(i)
6x + 5y = 115........(ii)
Multiply by 3 in equation 1
6x + 9y = 141
6x + 5y = 115
Now subtract the last equation from the above one
4y = 26
y = 6.50
For x, it would be
2x+ 3(6.50) = 47
2x + 19.5 = 47
2x = 47 - 19.50
2x = 27.50
x = 13.75
Hence, the large box weight is 6.50 kg and the small box weight is 13.75 kg
The right-end behaviour of all polynomials is always (i.e. whether highest power is odd or even) increasing when the leading coefficient (coefficient of the highest powered variable) is positive.
Otherwise, it is decreasing.
The leading coefficient is +3 (i.e. positive), corresponding to the term +3x^2.
I=prt
i=(45000)(0.08)(1)
i=3600
depreciation= $3600/y
Answer: the answer is option c
Step-by-step explanation:
