Answer:
315 chocolate
Step-by-step explanation:
Let Sam's chocolate be S
Let Clariss's chocolate be C
When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.
This can be written as:
C = 5S
The sum of their chocolate is 504 i.e
S + C = 504
Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:
S + C = 504
But: C = 5S
S + 5S = 504
6S = 504
Divide both side by 6
S = 504/6
S = 84.
C = 5S = 5 x 84 = 420
Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.
Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:
Amount of chocolate that Clarissa has a first = 420 – 105 = 315
Therefore, Clarissa had 315 chocolate at first.
Take a picture of your work and send it so I can help you
Answer:
y=5x+42
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(7-(-3))/(-7-(-9))
m=(7+3)/(-7+9)
m=10/2
m=5
y-y1=m(x-x1)
y-(-3)=5(x-(-9))
y+3=5(x+9)
y=5x+45-3
y=5x+42
Answer:
a) 
b) 
c) Mary's score was 241.25.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a) Find the z-score of John who scored 190
b) Find the z-score of Bill who scored 270
c) If Mary had a score of 1.25, what was Mary’s score?
Mary's score was 241.25.
Can you please take another picture that is closer to the diagram, it's quite blurry.
