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lukranit [14]
3 years ago
11

What is 6 to the second power divided by 2(3)+4=

Mathematics
2 answers:
Nuetrik [128]3 years ago
4 0
This same question its being asked a million times this week. But lets keep on working.

6² ÷ 2 (3) + 4

36/2 (3)+4

=(18)(3)+4

=54+4

=58

Alecsey [184]3 years ago
3 0
If you mean    <u>6²</u>
                 2(3)+4       that would be <u>36
</u>                                                         10   or 3.6
<u>
</u>If you mean 6²/2(3)+4  then 36/2=18 x 3= 54 +4=58 (following order of operation)

If you meant the first example I did,  I would have rewritten it as 
6² ÷ (2x3+4)= for clarity.  That would force me to do what is in parentheses first.
<u>
</u><u>
</u>
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8/15

Step-by-step explanation:

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In​ 2009, a diabetic express company charged ​$38.85 for a vial of type A insulin and ​$30.34 for a vial of type B insulin. If a
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The number of vials of type A insulin sold were _<u>21</u>__ and the number of vials of type B insulin sold were __<u>29</u>__.

Step-by-step explanation:

Let a = number of type A vials.

Let b = number of type B vials.

38.85a + 30.34b = 1695.71

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            38.85a + 30.34b = 1695.71

(+)        -38.85a - 38.85b = -1942.50

---------------------------------------------------

                               -8.51b = -246.79

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a + b = 50

a + 29 = 50

a = 21

Answer: The number of vials of type A insulin sold were _<u>21</u>__ and the number of vials of type B insulin sold were __<u>29</u>__.

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Which of the lines below is parallel to a line with a slope of three and Y intercept at (0, 3)
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Using the binomial distribution, it is found that there is a 0.0231 = 2.31% probability that the first person to say yes will occur with the seventh customer.

For each person, there are only two possible outcomes, either they say yes, or they say no. The probability of a person saying yes is independent of any other person, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
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  • p is the probability of a success on a single trial.

In this problem:

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.37)^{0}.(0.63)^{6} = 0.0625

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0.0231 = 2.31% probability that the first person to say yes will occur with the seventh customer.

A similar problem is given at brainly.com/question/24863377

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