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3 years ago

Find he value of x, round t nearest degree (sines and cosines)

Mathematics

2 answers:

Andrei [34K]3 years ago

7 0

Probably 62 is the right answer

larisa86 [58]3 years ago

4 0

You could reverse the triangle to look like a regular right triangle, making 7 on the bottom and 15 as the hypotenuse.
The height is about 13.2664991614216, which is rounded to 13
As long as we know the base and the hypotenuse we can calculate the value of x. If you do the math you get 62.181860715346076° which is rounded to 62<span>°

The answer is 62</span><span>°</span>

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The box plots show the average wind speeds, in miles per hour, for two different islands.

rewona [7]

Answer:

THE THIRD OPTION

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

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2 years ago

in class,12 students like to play vollyboll. if 30% of the students in the class like to play volleyball,how many students are i

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

Each strip is divided into 10 parts. 1/5 will be represented by 2 of those parts, so 2/5 will be represented by 4 of the 10 parts. The 3/10 used on the other gift will be represented by 3 additional parts. So, a total of 7 of the 10 parts of the strip need to be colored to represent the ribbon used.

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2 years ago

emily has a bowl of M&M's for every 25 M&M's there are blue 5 M&M's. what percent of her M&M's are blue

KonstantinChe [14]

Answer:

twenty percent.

Step-by-step explanation:

25/5=5

100/5=20

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2 years ago