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Temka [501]
2 years ago
15

Please help me find W Z U

Mathematics
1 answer:
Nana76 [90]2 years ago
6 0

Answer:

you can do it

Step-by-step explanation:

study to your self to make you smarter DJ meme MFC cjfkckskzkrkcjksskekcijrjvitjvjfjrkdkdkr cjdjf fkn fkf

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If I eat ¼ of ½ the pizza, how much will I have eaten
Nitella [24]

Answer:0.125

Step-by-step explanation:

1/4x 0.5

8 0
3 years ago
Read 2 more answers
Alexander is a high school basketball player. In a particular game, he made some two point shots and some three point shots. Ale
andrezito [222]

Answer:

2 three points shots and 4 two points shots

Step-by-step explanation:

Let x be the number of three points shots.

Alexander  made twice as many two points shots as three points shots, so the number of two points shots is 2x.

Amount earned in three points shots =3\cdot x

Amount earned in two points shots =2\cdot (2x)=4x

Total score =3x+4x=7x

Alexander scores a total of 14 points, then

7x=14\\ \\x=2\\ \\2x=2\cdot 2=4

7 0
3 years ago
Solve the equasion<br><br>2y-10y
Tamiku [17]
It’s -8y hope this help
3 0
3 years ago
The National Assessment of Educational Progress (NAEP) includes a mathematics test for eighth-grade students. Scores on the test
katovenus [111]

Answer:

1) The standard deviation of the sampling distribution is:

√ V(X[bar])= 0.3033

2) 95% of the values on the normal distribution are between μ ± 0.6066

3) The formula for the confidence interval is:

[284.5; 285.5]

Step-by-step explanation:

Hello!

Your study variable is

X: "score obtained on the test by an eighth-grader"

This variable has normal distribution:

X~N(μ;σ²)

Now the since the sample mean, X[bar], is obtained from n samples of the study variable, it is also a variable and has the same distribution as the original variable with the difference that is conditioned by the number of n samples from which it was calculated. So its distribution is:

X[bar]~N(μ;σ²/n)

Where E(X[bar])=μ and V(X[bar])= σ²/n

The sample information is:

n= 170100

X[bar]= 285

And the population standard deviation is known to be σ= 125.1

1) The standard deviation of the sampling distribution is:

√ V(X[bar]) = √(σ²/n) = σ/√n = 125.1/√170100 = 0.3033

2) 95% of the values on the normal distribution are between μ ± 2σ

This is μ ± 2*0.3033 = μ ± 0.6066

3) The formula for the confidence interval is:

X[bar] ± Z_{1-\alpha /2}*σ/√n

285 ± 1.64 * 0.3033

[284.5; 285.5]

I hope it helps!

7 0
3 years ago
1: Chris bought 12 feet of rope. How many inches of rope did he buy? 1ft = 12in
Delicious77 [7]
12 times 12 is 144 for the first one
and 300:0 i think
8 0
3 years ago
Read 2 more answers
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