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IgorC [24]
2 years ago
6

How do you do these math problem for exploring of algebra?

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
4 0

x=4

Step-by-step explanation:

4(-6+5x)=24+8x

open the bracket

-24+20x=24+8x

collect like terms

20x-8x=24+24

12x=48

divide both sides by 12

12x/12 = 48/12

x= 4

-7+7n=2(-7+7n)

open the brackets

-7+7n=-14+14n

collect like terms

14n-7n=-14+7

7n=-7

divide through by 7

n=-1

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​​​​​​​PLEASE HELP :((((
sertanlavr [38]

88(3.7+4.3)-2*2.6

88(8)-2*2.6

704-2*2.6

704-5.2

698.8

I hope it helps!

Please mark Brainliest if it does!:-)

5 0
2 years ago
Help me please I need help
balandron [24]

Answer:

I have solved the question in the picture in two different ways : simplification and factorisation I hope you find it useful bye:)

8 0
3 years ago
What is an equation of the line that passes through the point (-6, – 7) and is perpendicular to the line 6x + 5y = 30?
fomenos

Answer :6x + 5y = 30

5y = 30 - 6x

y = 6 - (6/5) x

So slope = -6/5

Perpendicular line has slope 5/6   (product of the slopes is -1)

So y = 5/6 x            +   b

Passed through (-6, -7) so           -7  =   -5  + b

Sp b = -2

So y = (5/6)x - 2

Step-by-step explanation:

3 0
2 years ago
A toy falls from a window 80 feet above the ground. How long does it take the toy to hit the​ ground?
andrew11 [14]

Answer:

2.24 s

Step-by-step explanation:

Given:

Δy = 80 ft

v₀ = 0 ft/s

a = 32 ft/s²

Find: t

Δy = v₀ t + ½ at²

80 ft = (0 ft/s) t + ½ (32 ft/s²) t²

t = 2.24 s

6 0
2 years ago
Suppose a football player kicks a ball and gives it an initial upward velocity of 47 ft/s. Use the formula h(t)= -16t^2+47t+3 wh
statuscvo [17]

Answer:

Step-by-step explanation:

a. when t=0,h=3ft

h(t)=-16 (t^2-\frac{47}{16}x+(\frac{47}{32} )^2)+\frac{47^2}{32^2} *16+3\\=-16(t-\frac{47}{32})^2+\frac{2209}{64}+3\\=-16(t-\frac{47}{32})^2+\frac{2209+192}{64}\\when~ t=\frac{47}{32}\\h=\frac{2301}{64}\\or~v^2-u^2=2gh\\\\0^2-47^2=2*(-32)h\\or h=\frac{47^2}{64}=\frac{2209}{64} \\height from the ground=\frac{2209}{64} +3=\frac{2301}{64}

c.t=47/32 sec

d.

time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2

t^2=\frac{2301}{64*16}

t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}

total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec

4 0
3 years ago
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