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nevsk [136]
3 years ago
13

Please Please Please help me with the answer

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

c = amount of chocolate donuts

m = amount of maple donuts.

so we know the total in all is 41 donuts, thus c + m = 41.

we also know that whatever c is, m is 25 fewer than that, m = c - 25.

\bf \begin{cases} c+m=41\\ \boxed{m}=c-25\\ --------\\ c+\boxed{c-25}=41 \end{cases} \\\\\\ 2c-25=41\implies 2c=66\implies c=\cfrac{66}{2}\implies c=33 \\\\\\ \stackrel{\textit{since c = 33}}{m = c - 25}\implies m=33-25\implies m = 8

Art [367]3 years ago
5 0
You need to set up an equation to solve this.

Let's say that the letter 'x' represents the number of chocolate donuts and the letter 'y' represents the number of maple donuts.

We know that if you add all the chocolate donuts and maple donuts together, you'll find the number of total donuts. We know that this number is 41 from the question.

Therefore, x + y = 41.

We know that there were 25 fewer maple donuts ('y' donuts) than chocolate donuts, meaning that if you take 25 away from whatever number of chocolate donuts there are (x donuts), you'll get the number of maple donuts.

Therefore, y = x - 25 (maple = chocolate - 25).

Now that we know what 'y' is in terms of 'x', we can substitute it into our original equation.

x + y = 41 becomes x + (x - 25) = 41. That's because I replaced the y with the equation we worked out above.

Therefore we have:

x + x - 25 = 41
2x - 25 = 41
2x = 66
x = 33.

Now that we've worked out what 'x' is (number of chocolate donuts), we can work out the number of maple donuts by taking away 25, because remember that the question says the number of maple donuts is equal to 25 taken away from the number of chocolate donuts. Therefore, 33 - 25 = 8.

There are 8 maple donuts. This also checks out because if you add the number of chocolate donuts and maple donuts together, you get 33 + 8 = 41, which is the total number of donuts.
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Juan has blue cubes with a 55 mm edge and red cubes with a 45 mm edge. He stacks them in two columns, one of each color; he wants the two columns to be the same height. How many cubes does he need, as a minimum, of each color?

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