<span>I'm guessing you are saying...
6, 12, 18, 24, 30, 36, 42, 48, 54, 60,
66, 72, 78, 84, 90, 96, 102, 108, 114, 120,
126, 132, 138, 144, 150, 156, 162, 168, 174, 180,
186, 192, 198, 204, 210, 216, 222, 228, 234, 240,
246, 252, 258, 264, 270, 276, 282, 288, 294, 300,
306, 312, 318, 324, 330, 336, 342, 348, 354, 360,
366, 372, 378, 384, 390, 396, 402, 408, 414, 420,
426, 432, 438, 444, 450, 456, 462, 468, 474, 480,
486, 492, 498, 504, 510, 516, 522, 528, 534, 540,
546, 552, 558, 564, 570, 576, 582, 588, 594, 600
Hope this helps ;)</span>
Answer:
C) 6 units
E) 8 units
Step-by-step explanation:
Kosi traced a rectangle on a coordinate grid. The rectangle had the following vertices: (−6, 5), (2, 5), (2, –1), and (–6, –1). Which of the following numbers are dimensions of the rectangle? Select each correct answer. A. 4 units B. 5 units C. 6 units D. 7 units E. 8 units F. 9 units. help, please!.
When given vertices for a geometric shapes we find the lengths of the side by using the formula:
When(x1, y1) and (x2, y2)
= √(x2 - x1)² + (y2 - y1)²
A= (−6, 5),B = (2, 5), C = (2, –1), and D = (–6, –1).
For AB
A= (−6, 5),B = (2, 5),
= √(2 -(-6)² + (5 - 5)²
= √8² + 0
= √64
= 8 units
For BC
B = (2, 5), C = (2, –1),.
√(2 - 2)² +(-1 - 5)²
= √0 + -6²
= √36
= 6 units
For CD
C = (2, –1), and D = (–6, –1).
= √(-6 -2)² + (-1 -(-1))²
= √-8² + 0²
= √64
= 8 units
For AD
A= (−6, 5), D = (–6, –1).
= √(-6 -(-6))² + (-1 - 5)²
= √0² + -6²
= √36
= 6 units
Therefore, the following numbers that are dimensions of the rectangle is
C) 6 units
E) 8 units
Answer:
$49425.1688842
Step-by-step explanation:
Use formula: v=c*(p^t), where v is the price now, c is the cost price, p is the 100-the depreciation percentage and t is the time/years passed)
0.9¹²(175000)
0.28242953648(175000)
49425.1688842
9514 1404 393
Answer:
- No Solution: A
- One Solution: B, C
- Infinitely Many Solutions: D
Step-by-step explanation:
Simplified, you will find the equations to be in one of three forms:
0 = 0 . . . . infinite solutions
a = 0 . . . . a≠0, no solutions
ax +b = 0 . . . one solution
To get one of these forms, we can subtract the right side of the equation from both sides, then simplify.
__
A. (u +2) -(u +5) = 0
-3 = 0 . . . . no solutions
__
B. (w +2) -(2w +5) = 0
-w -3 = 0 . . . . one solution
__
C. 3(w+2) -4(w+2) = 0
-w -2 = 0 . . . . one solution
__
D. (3(2x +5) -x) -(5(x +3)) = 0
6x +15 -x -5x -15 = 0
0 = 0 . . . . infinitely many solutions