Answer:
by using pemdas
Step-by-step explanation:
Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
= Answer:
Step-by-step explanation:
interest= 3500 * 6 * 6.9* 1/100
= 4949
Final value = £ 3500 + 1449
= 4949
Answer:
25
Step-by-step explanation:
b=4x+1 h=x+1 A=175
A=bh
Substitute: 175=(4x+1)(x+1)
Expand: 175=4x^2+5x+1
Subtract 175
4x^2+5x-174=0
Solve w/quadratic formula
(-5 <u>+</u> sqrt(25+2784))/8
Simplify: x=6 or -29/4
Distance is positive, so x=6
4x+1=4*6+1=25
Answer:
C. x < 40
Step-by-step explanation:
x/5 - 3 < 5
x/5 -3 + 3 < 5 + 3
x/5 < 8
(5/1) x/5 < 8 (5/1)
x < 40
