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KATRIN_1 [288]
3 years ago
12

At the movie theater Leon can buy 4 large popcorns or 2 large popcorns and 3 candy bars for the same price. If the candy bars co

st $6 each, how much is one large popcorn?
Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0
4p = 2p + 3c....p = popcorn, c = candy bars
c = 6

4p = 2p + 3(6)
4p = 2p + 18
4p - 2p = 18
2p = 18
p = 18/2
p = 9......whoa....9 bucks for popcorn....nothing is cheap anymore
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Simplify the fraction completely.
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Answer:

5

Step-by-step explanation:

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Why do whole numbers raised to an exponent get bigger while fractions raised to an exponent get smaller
Brilliant_brown [7]

Answer:

when you multiply a whole number by itself it will obviously get bigger.

4 to the 2nd power equals 16 because 4x4 = 16

if you were to multiply a smaller number though, it wouldn't get as big.

Each number you put to the same exponent will not get bigger at the same rate since each number isnt being multiplied by the same thing.

ex. 4 and 6 are raised to the second power both dont get multiplied by the same number 4 is multiplied by 4, and 6 by 6, therefore the bigger the number the bigger it grows.

Fractions get smaller for this reason when you have the fraction 2/3 raised to the second, both numbers must be raised. 2 to the second equals 4 while 3 to the second is 9.

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Step-by-step explanation:

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3 years ago
Which expression is a possible leading term for the polynomial function graphed below?
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a

Step-by-step explanation:

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Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

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