All categories

2 years ago

It cost $4 to enter a fair. Each ride costs $2.50. You have 21.50. How many rides can you go on

Mathematics

1 answer:

jekas [21]2 years ago

4 0

Answer:

7 rides

Step-by-step explanation:

So you start off with $21.50. Subtract $4 from 21.50 and you'll end up with $17.50. Now divide $17.50 with the price of each ride which is $2.50 and you end up with 7. You are able to go on 7 rides.

You might be interested in

Solve.<br><br> m - 15 = 20<br><br> m =

Fittoniya [83]

$\text{Hello There!}$

$\text{We are going to need to isolate the variable}$

$m - 15 = 20$

$\text{Add 15 to both sides.}$

$\text{We do this because we need to perform inverse operations to find}$ $\text{the value of the variable.}$

$m - 15 + 15 = 20 + 15 = 35$

$\fbox{Therefore, your answer is going to be 35.}$

$\rule{300}{1.5}$

7 0

2 years ago

Read 2 more answers

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

5 months ago

A) 4

Shkiper50 [21]

Answer:

i think c

Step-by-step explanation:

8 0

2 years ago

What is her answer ?

mihalych1998 [28]

Answer:

lolz sorry for a late answer bud

Step-by-step explanation:

7 0

3 years ago

100 = 10 to the power of what

Greeley [361]

Answer:

10 to the power of 2

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers