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lions [1.4K]
3 years ago
5

It cost $4 to enter a fair. Each ride costs $2.50. You have 21.50. How many rides can you go on

Mathematics
1 answer:
jekas [21]3 years ago
4 0

Answer:

7 rides

Step-by-step explanation:

So you start off with $21.50. Subtract $4 from 21.50 and you'll end up with $17.50. Now divide $17.50 with the price of each ride which is $2.50 and you end up with 7. You are able to go on 7 rides.

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Answer:

19/4

Step-by-step explanation:

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PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!
shutvik [7]

Answer:

m\angle N = 32\degree

m\widehat {NQ}=106\degree

Step-by-step explanation:

By inscribed angle theorem:

m\angle N = \frac{1}{2} \times m\widehat {MP}

m\angle N = \frac{1}{2} \times 64\degree

m\angle N = 32\degree

Again by inscribed angle theorem:

m\angle P= \frac{1}{2} \times m\widehat {NQ}

53\degree = \frac{1}{2} \times m\widehat {NQ}

2\times 53\degree = m\widehat {NQ}

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5,900 round to the nearest thousand
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The answer is six thousand
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Valerie’s meal costs $32.75 and Derek’s meal costs $39.88. Valerie treats Derek by paying for both meals, and leaves a 14%tip. F
boyakko [2]
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5 0
3 years ago
Read 2 more answers
Enter the missing numbers in the boxes to complete the table of equivalent ratios of time to distance.
andre [41]
Answer:  Here is the complete table, with the filled in values:
______________________________________________________________
Time (h)    Distance (mi)
    3                2 
    9                6
   12                8
   18               12
___________________________________________________

Explanation:
___________________________________________________
Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
         when the time (in "h") is "18" ; 
___________________________________________________

12/8 = 18/?  

Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;

Rewrite:  3/2 = 18/? ;  cross-multiply:  3*? = 2 * 18 ; 
                                                                        3*? = 36 ;

                                                                      Divide each side by "3" ;
                                                                            The "?" = 36/3 = 12 ;

So, 12/8 = 18/12 ;

The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
                              when the "time" (in "h") is "18".
__________________________________________________________
Now, let us obtain the "? " value for the "distance" (in "mi.");
                when the "time" (in "h") is:  "9" .

12/8 = 9/? ;  Solve for "?" ;

We know (see aforementioned) that "12/8 = 3/2" ; 

So, we can rewrite:  3/2 = 9/? ;  Solve for "?" ; 

Cross-multiply:  3* ? = 2* 9 ;    3* ? = 18 ;  
                                                           Divide each side by "3" ;
                                                    to  get:  "6" for the "?" value.

When the time (in "h") is "9", the distance (in "mi.") is "6" .
____________________________________________________
Now, to solve the final "?" value in the table given.

9/6 = ?/2 ;  Note:  We get the "6" from our "calculated value" (see above problem). 

9/6 = (9÷3) / (6÷3) = 3/2 ;  

So, we know that the "?" value is:  "3" .

Alternately:   9/6 = ?/2 ; 

Cross-multiply:  6*? = 2*9 ;   6 * ? = 18 ;  Divide each side by "6" ;
                                                               to find the value for the "?" ; 
                                                                    "?" = 18/6 = "3" .

When the "distance" (in "mi.") is:  "2" ;  the time (in "h") is:  "3" .
____________________________________________________
Here is the complete table—with all the values filled in:
____________________________________________________

<span>Time (h)    Distance (mi)
____________________________________________________
    3                2 
    9                6
   12                8
   18               12
____________________________________________________
</span>
6 0
3 years ago
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