I don’t that’s a question
Answer:
ABCD and EFGH
ABCD and PQRS (or EFGH and PQRS)
Dilate by a scale factor of 3
Step-by-step explanation:
Congruent means they have the same shape and size.
Similar means they have the same shape, but not necessarily the same size.
The orientation (rotation angle) or position do not matter.
EFGH is reflected and rotated, so it maintains the same shape and size as ABCD. Therefore, they are congruent.
PQRS is scaled and translated, so it has the same shape, but different size than ABCD. Therefore, they are similar but not congruent.
Also, PQRS is similar to EFGH, but not congruent.
To make EFGH congruent to PQRS, we need to make it the same size. So we need to scale EFGH by a factor of 3.
Answer: 5+d
Step-by-step explanation:
More means adding and it doesn't matter which order you put it in in adding.
If the shape of the room is a square, then the square root of the sum of the squares of the the two adjacent sides will give the diagonal.
i.e.
Since the square root of the sum of the squares of the the two adjacent sides is 24.04 and not 18.79, therefore, the shape of the room is not a square.
The function, as presented here, is ambiguous in terms of what's being deivded by what. For the sake of example, I will assume that you meant
3x+5a
<span> f(x)= ------------
</span> x^2-a^2
You are saying that the derivative of this function is 0 when x=12. Let's differentiate f(x) with respect to x and then let x = 12:
(x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
[x^2-a^2]^2
(144-a^2)(3) - (36+5a)(24)
------------------------------------ = 0
[ ]^2
Simplifying,
(144-a^2) - 8(36+5a) = 0
144 - a^2 - 288 - 40a = 0
This can be rewritten as a quadratic in standard form:
-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.
Solve for a by completing the square:
a^2 + 40a + 20^2 - 20^2 + 144 = 0
(a+20)^2 = 400 - 144 = 156
Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)
Finally, a = -20 plus or minus 2sqrt(39)
You must check both answers by subst. into the original equation. Only if the result(s) is(are) true is your solution (value of a) correct.
