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Usimov [2.4K]
3 years ago
6

Help solve: 2t^3-t-10

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0
<span>2t^3-t-10=
+10 on both sides
2t^3-t=10
t^3=10
cube both sides by 3
t=1000</span>
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Factor by Grouping.
Komok [63]

Answer:

The ac product of 35x^2+41x+12 is <u>420</u>.

The factors of the ac product that add to 41 are <u>20</u> and <u>21</u>.

35x^2+41x+12 = (7x+4)(5x+3)

Step-by-step explanation:

1) The general form of a quadratic is ax^2 + bx + c. Hence, multiplying 35 by 12 gives you the product of ac, which is 420.

2) We need to find two numbers that multiply to 420 and add up to 41 <u>simultaneously</u>. If we pull out the factors of 420, two of them will be 20 and 21, which multiply to 420 as well as add up to 41.

3) Write 41x as a sum.

35x^2+20x+21x+12

Now, we can factor them out by grouping.

35x^2+20x+21x+12\\5x(7x+4)+3(7x+4)

Since, 7x +4 is common in both of the factors, we only take one of the 7x+4 along with 5x and 3.

(7x+4)(5x+3)

6 0
2 years ago
Read 2 more answers
Let n =21. What is the value of n + 10?
Sergio039 [100]
I think it is 21+10=31...
3 0
4 years ago
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Find the 4th term in the sequence with the following definition:<br> Please help me!!
tigry1 [53]

Answer:

256

Step-by-step explanation:

Using the recursive formula and a₁ = 2, then

a₂ = a₁² = 2² = 4

a₃ = a₂² = 4² = 16

a₄ = a₃² = 16² = 256

Thus the 4 th term is 256

8 0
3 years ago
What is the square root of 10
olga nikolaevna [1]
Lol, I think its 3.16 but I am not sure. :(

4 0
3 years ago
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Find an equation for the perpendicular bisector of the line segment whose endpoints are (5,-9)and (-9,-5)
Papessa [141]

Answer:

y = ¹⁴/₄.x

Step-by-step explanation:

First of, if the bisector is perpendicular to the line segment, then we can find the gradient of the bisector (m_{b}) using the rule/principle:

Let:

m = gradient of the line segment

Then:

m_{b} = -\frac{1}{m}

We can find m since we have two points that fall on the line segment, (5, -9) and (-9, -5):

m = Δy/Δx

m = \frac{-9 - (-5)}{5 - (-9)} \\\\ m = -\frac{4}{14}

We can now find m_{b}:

m_{b} = -\frac{1}{(-\frac{4}{14}) } \\\\ m_{b} = 1.\frac{14}{4} \\\\ m_{b} = \frac{14}{4}

The equation of a line can be found using:

y - y₁ = m(x - x₁)

We have the gradient of the perpendicular bisector, the only other thing we need to identify the equation of the bisector is coordinates of a point that fall on the line;

We know the line will pass through the point exactly midway between (5, -9) and (-9, -5) since it is a bisector;

This can be found by:

x_{1} = -9 + \frac{5 - (-9)}{2} \\ x_{1} = -9 + 7 \\ x_{1} = -2 \\\\ y_{1} = -5 + \frac{-9 - (-5)}{2} \\ y_{1} = -5 +(-2) \\ y_{1} = -7 \\\\ (-2, -7)

We have a point on the line and the gradient so we can now find the equation:

y - (-7) = \frac{14}{4}(x - (-2)) \\\\ y + 7 = \frac{14}{4}(x + 2) \\\\ 4y + 28 = 14(x + 2) \\\\ 4y + 28 = 14x + 28 \\\\ 4y = 14x \\\\ y = \frac{14x}{4}

8 0
3 years ago
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