All categories

3 years ago

6m+7n+5m-3n how do I solve

Mathematics

2 answers:

Wewaii [24]3 years ago

6 0

combine like terms, so 6m + 5m =11m

then 7n - 3n = 4n

ANSWER: 11m+4n

anygoal [31]3 years ago

3 0

Here i will help you through the steps

1.) write the problem 6m+7n+5m-3n

2.) now group the like terms like 6m+5m and 7n-3n

3.) now solve 6m+5m and 7n-3n

4.) your answer should be 11m+4n

5.) thats how you solve it, Have a great day!

You might be interested in

Hector has three weeks before his first track meet he recorded the amount of time he spent running during week 1 of his training

Fofino [41]

Add them all up so 2 6/12 and 1 6/12 is 4 and then add 1 9/12 to get 5 9/12 or in simple form 5 3/4

6 0

3 years ago

Your answer should be a polynomial in standard form. (x + 5)(x +3)=(x+5)(x+3)

sattari [20]

Answer:

∴(x+5)(x+3) =x²+8x+15

Step-by-step explanation:

Standard form of a polynomial:

Standard of polynomial means that the terms ordered from biggest exponent of variable to lowest exponent of variable.

Example:

$a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+......$

Given,

(x+5)(x+3)

=x(x+3)+5(x+3)

=x²+3x+5x+15

=x²+8x+15

∴(x+5)(x+3) =x²+8x+15

The degree of the polynomial is 2 and is a one variable polynomial.

7 0

2 years ago

Only 0.6% of the students at a high school did not attend the first football game. Write 0.6% as a fraction and as a decimal

Afina-wow [57]

Answer:

here my answer

Step-by-step explanation:

hope this helps

5 0

2 years ago

Plz help anyone please

madam [21]

If you wanted to go to the gym for only 4 months basic gym would be cheaper but if you wanted to go for a whole year then you’d spend less money at the holiday gym

Hope thia helped can you mark me brainliest please

8 0

2 years ago

Read 2 more answers

Please help. I've been trying to figure this out for an hour and I still don't understand how it's 72. I feel really stupid beca

rosijanka [135]

Answer:

C. $72\pi$

Step-by-step explanation:

The radius of the circle is 24 units, then the area of the whole circle is

$\pi r^2=\pi \cdot 24^2=576\pi \ un^2.$

The shaded circle is limited by 45° angle, so its area is

$\dfrac{45}{360}=\dfrac{1}{8}$

of the area of the whole circle.

The area of the shaded circle is

$\dfrac{1}{8}\cdot 576\pi =72\pi \ un^2.$

3 0

3 years ago