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3 years ago

6m+7n+5m-3n how do I solve

Mathematics

2 answers:

Wewaii [24]3 years ago

6 0

combine like terms, so 6m + 5m =11m

then 7n - 3n = 4n

ANSWER: 11m+4n

anygoal [31]3 years ago

3 0

Here i will help you through the steps

1.) write the problem 6m+7n+5m-3n

2.) now group the like terms like 6m+5m and 7n-3n

3.) now solve 6m+5m and 7n-3n

4.) your answer should be 11m+4n

5.) thats how you solve it, Have a great day!

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Suppose that 10% of the fields in a given agricultural area with about 2,500 fields are infested with the sweet potato white fly

aleksley [76]

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a. 250 fields

b. 220 to 280 fields

c. Fields are not independent

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a. The average number of fields sampled that are infested with whitefly =

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= 2500 X 10% = 250 fields

b. Going by the binomial distribution is the square of the standard deviation, divided by (the product of the sample size n, and the probability a and b). While the standard deviation is the square root of the variance

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= √225 = 15

Now let's use the empirical rule that says about 95% of the observations are within two standard deviations from the mean since the number of trials is very large

μ - 2σ = 250 - 2(15) = 220

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Approximately 220 to 280 fields are expected to be infested going by 95% probability observation

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5 0

2 years ago

Xpand the binomial (4x + 3y)3. The coefficient of the second term in the expansion of the binomial (4x + 3y)3 is .

Ad libitum [116K]

Answer: 144

Step-by-step explanation:

The binomial is $\left( 4x+3y\right)^3$

The expansion of $\Rightarrow \left ( a+b \right )^n=^nC_0\left ( a \right )^n\left ( b \right )^0+^nC_1\left ( a \right )^{n-1}\left ( b \right )^1+^nC_2\left ( a \right )^{n-2}\left ( b \right )^2+^nC_3\left ( a \right )^{n-3}\left ( b \right )^3+\ldots$

Expansion of $\left( 4x+3y\right)^3$

$\Rightarrow ^3C_0\left ( 4x\right )^{3}\left ( 3y\right )^0+^3C_1\left ( 4x\right )^{2}\left ( 3y\right )^1+^3C_2\left ( 4x\right )^{1}\left ( 3y\right )^2+^3C_3\left ( 4x\right )^{0}\left ( 3y\right )^3$

So, the second term is

$\Rightarrow ^3C_1\left ( 4x\right )^{3-1}\left ( 3y\right )^1\\\Rightarrow ^3C_1\left ( 4x\right )^{2}\left ( 3y\right )^1$

Its Coefficient is

$\Rightarrow ^3C_1\times 4^2\times 3\\\Rightarrow 3\times 16\times 3=144$

6 0

3 years ago