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Andre45 [30]
2 years ago
14

I need help solving this

Mathematics
1 answer:
Viktor [21]2 years ago
5 0

Answer:

x = 46 :)

Step-by-step explanation:

First we subtract :)

180 - 88 = 92

Now we divide :)

92/2 = 46

Now you know how to solve this type of problem!!

Have an amazing day!!

Please rate and mark brainliest!!

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3/4(x + 3) = 9<br><br><br> How do I solve this
Sonbull [250]

Answer:

x = 10

Step-by-step explanation:

so first distribute the 3/4 to everything on the inside

3/4x + 1 1/2 = 9

now subtract 1 1/2 on both sides

3/4x = 7 1/2

Now divide both sides by 3/4

x = 7 1/2 divided by 3/4

x = 15/2 divided by 3/4

x = 15/2 times 4/3

x = 5/1 times 2/1

x = 10

4 0
2 years ago
What is the coefficient of y in the expression 3 ⋅ 4 + 5y?
ZanzabumX [31]
<h3>Answer: 5</h3>

The coefficient is the term just to the left of the variable. So for the term 5y, the number to the left of y is 5.

extra info: 5y is the same as 5*y or "5 times y", where y is a placeholder for some unknown number.

7 0
3 years ago
Read 2 more answers
How to solve the function 4y+x=12
Sidana [21]
First you rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation

Second you solve it by using the formula of a straight line drawn on Cartesian coordinate system in which “y” is the vet risk axis and “x” the horizontal axis.
7 0
2 years ago
What is the length of the hypotenuse of the triangle?<br> A<br> 7 cm<br> B<br> 3 cm
photoshop1234 [79]

Answer

The answer would be 58

Step-by-step explanation:

3 to the power of 2 is 9

7 to the power of 2 is 49

add that you get 58

3 0
3 years ago
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
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