Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Which type of divison is needed for this problem
Polynomial or Simple?
8 - 11 = -3. The square root of 25/121 = (the square root of 25) / (the square root of 121) = 5/11 . -3 x 5/11 = -3/1 x 5/11 = (-3 x 5) / (1 x 11) = (-15)/11 = -15/11.
Hi will read 1,400 pages each day if he reads the book
The median is the middle line. Range is the the lowest value subtracted from the highest value. Mode is the most often occurring number. The mean is the average of all the data.
