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3 years ago

128 is the product of hectors score and 8 Fastest answer will be the brainliest

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

The equation would be 8h= 128

Step-by-step explanation:

Norma-Jean [14]3 years ago

5 0

Answer:

Step-by-step explanation:

When you divide both sides by 8, you end up with:

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Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $17 comma 90017,900

Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of line is

$y-17900=\frac{20300-17900}{4-1}(x-1)$

$y-17900=\frac{2400}{3}(x-1)$

$y-17900=800(x-1)$

$y-17900=800x-800$

Add 17900 on both sides.

$y=800x-800+17900$

$y=800x+17100$

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

$30700=800x+17100$

Subtract 17100 from both sides.

$30700-17100=800x$

$13600=800x$

Divide both sides by 800.

$\frac{13600}{800}=x$

$17=x$

Therefore, in 17th year his income was $30,700.

5 0

3 years ago

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the

uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is $\rm M = log\left ( \dfrac{10S}{S}\right )$ .

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

$\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1$

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is $\rm M = log\left ( \dfrac{10S}{S}\right )$ .

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

5 0

2 years ago

Find the complete factored form of the polynomial<br> 28a^4b^6 + 21a^3b^6

n200080 [17]

Yes the fierce rbajeei ironwood he

3 0

3 years ago

What is 8/36 in simplest form

Maksim231197 [3]

8/36
Divide the numerator and the denominator by 4
2/9
That's the simplest form
Have an awesome day! :)

4 0

4 years ago

Read 2 more answers

What are the vertex focus and directrix of a parabola with equation x=y^2+14y-2

zimovet [89]

This is a sideways opening parabola, opening to the right to be more specific, since the leading coefficient is a positive 1. The rule for a focus and a directrix is that they are the same number of units from the vertex (in other words, the vertex is dead center between them), and that the vertex is on the same axis that the focus is. We need to find the vertex then to determine what the focus and the directrix are. We will complete the square on that to find the vertex. Begin by setting it equal to 0, then move the 2 over by addition to get $y^2+14y=2$ . Now we will complete the square on the y terms. Take half the linear term, square it, and add it to both sides. Our linear term is 14. Half of 14 is 7, and 7 squared is 49. So we add 49 to both sides. $y^2+14y+49=2+49$ , which of course simplifies to $y^2+14y+49=51$ . The purpose of this is to find the k coodinate of the vertex which will be revealed when we write the perfect square binomial we created during this process: $(y+7)^2=51$ . Moving the 51 back over by subtraction gives us $(y+7)^2-51=x$ . The vertex then is (-51,-7). The formula to find the focus using this vertex is $(h+ \frac{1}{4a},k)$ . As I stated quite a while ago, the leading coefficient on our parabola was a +1 so our "a" value is 1, and the focus is then found in $(-51+ \frac{1}{4},-7)$ which simplifies to $(-50.75, -7)$ . If the vertex is (-51, -7) and the focus is (-50.75, -7), then the distance between them is 1/4, or .25. That means that the directrix is also .25 units from the vertex, but in the other direction. Our directrix is a vertical line, and it will have the equaion x = -51.25. Summing up, your focus is (-50.75, -7) and your directrix is x = -51.25

7 0

4 years ago