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oee [108]
3 years ago
9

Please Help, I really don't get it

Mathematics
1 answer:
mariarad [96]3 years ago
6 0
Miles will be spending less than last week because 2/3 is less than one.
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CAN ANYBODY PLS HELP
Firdavs [7]

The correct options are

5x =  - 58 \:5x + 4 =  - 54

<h3>How to find same value of x?</h3>

given that

\frac{5}{6} x +  \frac{2}{3}  =  - 9

first find value of x to obtain the equations have the same value of x.

Find the L.C.M between the 6,3

\frac{5x + 4}{6}  =  - 9

Then Cross multiplication should be done

5x + 4 =  - 9 \times 6 \\ 5x + 4 =  - 54 \\ 5x =  - 54 - 4

5x =  - 58

Hence the correct options are

5x =  - 58

5x + 4 =  - 54

Learn more about problems on equations, refer:

https://brainly.in/question/742266

#SPJ9

7 0
1 year ago
Workers are installing new seats in the football stadium with the team colors.Starting with the first row, every sixth row of se
evablogger [386]

Answer:

red cuz its an odd number so every even number row is blue

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the volume of the right prism? ______ft3
oksian1 [2.3K]
Volume = Length x Width x Height

Length = 4 ft
Width = 4 ft
Height = 15 ft

Volume = 4 ft x 4 ft x 15 ft = 240 ft^3
4 0
3 years ago
1.
kicyunya [14]

Answer:

D. p = 6.25h

Step-by-step explanation:

6.25 (2) = p 12.50

6.25 (4) = p 25.00

6.25 (6) = p 37.50

6.25 (8) = p 50.00

7 0
3 years ago
Jennifer got a box of chocolates. the box is a right triangular prism shaped box. it is 7 in long. and the triangular base measu
Lera25 [3.4K]

Answer:

A = 68.8 inches^{2}

Step-by-step explanation:

Given : Jennifer got a box of chocolates. the box is a right triangular prism shaped box. it is 7 in long. and the triangular base measure 2in times 3in times 4in.

a = 2

b=3

c=4

To Find : what is the surface area of the box of chocolates?

Solution: The first thing we should know is the area of the triangular base.

 Triangular base area: 

A1 =\sqrt{(s * (s-a) * (s-b) * (s-c)) }

 Where, s is the semi-meter of the triangle:

s =\frac{ (a + b + c) }{ 2}

 a, b, c: sides of the triangle.

 Substituting:

 s = (2 + 3 + 4) /2=4.5

A1 = \sqrt{ (4.5 * (4.5-2) * (4.5-3) * (4.5-4))}

 A1 = 2.90

 Then, you must know the area of each rectangle associated with each side of the triangular base.

 Rectangle area 1: Ar1 = (a) * (l)

                              Ar1 = (2) * (7)

                              Ar1 = 14

 Rectangular area 2:   Ar2 = (b) * (l)

                                    Ar2 = (3) * (7)

                                    Ar2 = 21

 Rectangular area 3:   Ar3 = (a) * (l)

                                    Ar3 = (4) * (7)

                                    Ar3 = 28

 Finally the surface area is: A = Ar1 + Ar2 + Ar3 + 2 * A1

                                             A = (14) + (21) + (28) + 2 * (2.90)

                                            A = 68.8 inches^{2}

 Hence the surface area of the box of chocolates is 

A = 68.8 inches^{2}

6 0
3 years ago
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