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leva [86]
3 years ago
14

Find the product. 76x327

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0
Answer: 24,852

76 x 327 = 24852

OR

327
  76
-------
24852
---------
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B. The school prom committee sold presale tickets for
Ivan

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334      Eqn 1

18x+24y=7320    Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012      Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

6y=1308

\frac{6y}{6}=\frac{1308}{6}\\y=218

Therefore,

218 students purchased tickets at the dance.

5 0
3 years ago
George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
Two numbers have a sum of 9 when added together.
antiseptic1488 [7]

Answer:40

Step-by-step explanation:+$)#)#

5 0
3 years ago
1,2,4,7,11,16,22, ___,____<br> What is the rule?
Paha777 [63]
Find rates of change until you find a constant.

dy/dx=1,2,3,4,5,6

d2y/dx2=1,1,1,1,1  

So the acceleration, d2y/d2x, is constant.  This means that this is a quadratic sequence of the form a(n)=an^2+bn+c.  So we can set up a system of equations to solve for the values of a,b, and c.  Using the first three points, (1,1), (2,2), and (3,4) we have:

9a+3b+c=4, 4a+2b+c=2, and a+b+c=1  getting the differences...

5a+b=2 and 3a+b=1  and getting this difference...

2a=1, so a=1/2 making 5a+b=2 become:

2.5+b=2, so b=-1/2, making a+b+c=1 become:

1/2-1/2+c=1, so c=1  so the rule is:

a(n)=0.5x^2-0.5x+1  or if you prefer to not have decimals

a(n)=(x^2-x+2)/2
6 0
3 years ago
Read 2 more answers
(-24)+19= please let me know​
exis [7]

Step-by-step explanation:

(-24)+19

= 19 - 24

= -5 (Ans)

7 0
3 years ago
Read 2 more answers
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